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Rashid [163]
3 years ago
7

35 points to help me i wrote the definition up top for this i just need help using it in a Example/Sentence

Chemistry
1 answer:
dmitriy555 [2]3 years ago
5 0

In order for a cellular device to operate, it requires battery power, otherwise known as energy.

or you can do this

Us humans consume food so that we can have the sufficient energy to accomplish tasks.

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How can you tell isotopes of the same element apart?
liberstina [14]
We can differentiate them on the basis of their mass numbers. Isotopes have same atomic number but different mass number.
8 0
3 years ago
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How many grams of NaF should be added to 500 mL of a 0.100 M solution of HF to make a buffer with a pH of 3.2
Korolek [52]

Answer:

2.25g of NaF are needed to prepare the buffer of pH = 3.2

Explanation:

The mixture of a weak acid (HF) with its conjugate base (NaF), produce a buffer. To find the pH of a buffer we must use H-H equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer that you want = 3.2, pKa is the pKa of HF = 3.17, and [] could be taken as the moles of A-, the conjugate base (NaF) and the weak acid, HA, (HF). </em>

The moles of HF are:

500mL = 0.500L * (0.100mol/L) = 0.0500 moles HF

Replacing:

3.2 = 3.17 + log [A-] / [0.0500moles]

0.03 = log [A-] / [0.0500moles]

1.017152 = [A-] / [0.0500moles]

[A-] = 0.0500mol * 1.017152

[A-] = 0.0536 moles NaF

The mass could be obtained using the molar mass of NaF (41.99g/mol):

0.0536 moles NaF * (41.99g/mol) =

<h3>2.25g of NaF are needed to prepare the buffer of pH = 3.2</h3>
4 0
3 years ago
26 PONITS FOR BEST ANSWER
Ivenika [448]
A

C

D

C
 
trust me plz i am good at chemistry
3 0
4 years ago
For which element are the number of protons, electron, and neutrons are 36, 36, and 48 respectively? a cadmium b rubidium c brom
Anna71 [15]
Krypton has 36 protons and electrons and 48 neutrons. 
5 0
3 years ago
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Calculate the mass of water produced when 5.87 g of butane reacts<br> with excess oxygen.
Iteru [2.4K]

Answer:

Explanation:

no. of moles of butane = 5.87g / 58.124 = 0.1009mol

since O2 is excess, limiting reagent is butane

from the equation, 2 moles of butane will reacted to produce water = 10 moles

therefore, 0.1009 moles of butane produced water = (0.1009 x 5) = 0.5050 moles

Weight of H2O formed = 0.5050 x 18.015 = 9.10 grams

8 0
3 years ago
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