1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
netineya [11]
3 years ago
10

A nuclear waste site. cesium-137 is a particularly dangerous by-product of nuclear reactors. it has a half-life of 30 years. it

can be readily absorbed into the food chain and is one of the materials that would be stored in the proposed waste site at yucca mountain (see the article opening this section). suppose we place 3000 grams of cesium-137 in a nuclear waste site.how much cesium-137 will be present after 60 years, or two half-lives?
Chemistry
1 answer:
hram777 [196]3 years ago
4 0
The mass decay rate is of the form
m(t) = m_{0} e^{-kt}
where
m₀ = 3000 g,the initial mass
k = the decay constant
t = time, years.

Because the half-life is 30 years, therefore
e^{-30k} =  \frac{1}{2} \\\ -30k = ln(0.5) \\ k =  \frac{ln(0.5)}{-30} =0.0231

After 60 years, the mass remaining is
m = 3000 e^{-0.0231*60} = 750 \, g

Answer: 750 g

You might be interested in
How is an oxidation half-reaction written using the reduction potential chart? How is the oxidation potential voltage determined
insens350 [35]
Oxidation  half  reaction  is  written   as    follows when  using  using  reduction potential  chart
example  when  using  copper  it is  written  as  follows
CU2+   +2e-  --> c(s)  +0.34v
 oxidasation  is the  loos  of  electron  hence copper oxidation  potential  is  as  follows
cu (s)  -->  CU2+   +2e    -0.34v

7 0
3 years ago
Read 2 more answers
Which statement is correct for the element of proton number 19?
BlackZzzverrR [31]

Answer:

D

Explanation:

From periodic table : proton number 19  corresponds to K  (potassium)

  which is very reactive with water

8 0
2 years ago
Assume a hydrogen atom has an electron in the n-level corresponding to the month of your birthday (jan = 1, feb = 2, etc.) calcu
luda_lava [24]
My Birthday is in April, So, electron of H atom is in n=4( pfund series).

Ionisation Energy= +13.6(z^2/n^2)
= +13.6(1/16)
= +0.85 eV
6 0
3 years ago
Read 2 more answers
Help please. I only need the concepts.
melomori [17]

Boyle’s = increase as volume decreases

Charles = increases and pressure increases

Gay-lussacs = increases as pressure increases

5 0
3 years ago
Calculate the molarity and normality of 5.7 g of Ca(OH)2 in 450 mL of solution.
Kisachek [45]
  The  molarity   and  normality  of  5.7 g  of  Ca(OH)2   in  450ml  0f    solution  is  calculated  as  follows

molarity  =  moles/volume in  liters
moles  =mass/molar  mass
=  5.7g/74g/mol  =  0.077moles
molarity =  0.077/450  x1000= 0.17M

Normality =  equivalent  point  x molarity
equivalent  point  of Ca(OH)2  is  2   since  it has  two  Hydrogen  atom

normality  is therefore =  0.17  x2 = 0.34 N
7 0
3 years ago
Other questions:
  • How many moles are 1.20 x 1025 formula units of calcium iodide?
    10·1 answer
  • Which metal in Period 5 is very reactive and has two valence electrons in each atom?
    7·2 answers
  • calculate the number of moles of gas that occupy a 3.45L container at a pressure of 1.48 atm and a temperature of 45.6 Celsius ​
    6·1 answer
  • How many liters of ethylene glycol antifreeze (C 2H 6O 2) would you add to your car radiator containing 15.0 L of water if you n
    8·1 answer
  • How is modeling useful to scientists?
    5·1 answer
  • PLEASE HELP, WILL MARK BRAINLIEST!!!!! TIME IS RUNNING OUT!!!!
    14·1 answer
  • A 25.0 mL aliquot of 0.0430 0.0430 M EDTA EDTA was added to a 56.0 56.0 mL solution containing an unknown concentration of V 3 +
    15·1 answer
  • I NEED HELP PLEASE! ITS DUE IN 30 MINUTES
    8·1 answer
  • The mass of 900. atoms of sodium(Na)
    11·1 answer
  • Answer the question on the screen, “What type of bond is this combination likely to form?”
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!