We can solve this problem using the long hand solution, wherein we 1 by 1 analyze the different equilibrium reactions or by simply using the Henderson Hasselbach equation. The equation is
pH = -log(pKa) + log (salt/acid)
since the acid and the salt have the same concentration, the log (salt/acid) term is equal to zero.
thus
pH = -log(1.73*10-5)
pH = 4.76
please be careful with the negative sign
A solution in which methyl orange is red indicates the most acidic substance.
<h3>What is an Indicator?</h3>
This is defined as a substance that gives a visible sign, usually by a colour change when a chemical species is added.
On litmus paper, the redder the color is, the more acidic it is which was why methyl orange changing to darker red signifies most acidity.
Read more about Indicator here brainly.com/question/1918667
Answer:
1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
2.6592 grams of oxygen remain in the flask.
Explanation:
Volume of the flask remains constant = V = 2.0 L
Initial pressure of the oxygen gas = 
Initial temperature of the oxygen gas = 
Final pressure of the oxygen gas = 
Final temperature of the oxygen gas = 
Using Gay Lussac's law:


1.27 atm is the final pressure of the oxygen in the flask (with the stopcock closed).
Moles of oxygen gas = n
(ideal gas equation)

Mass of 0.08310 moles of oxygen gas:
0.08310 mol × 32 g/mol = 2.6592 g
2.6592 grams of oxygen remain in the flask.
Answer 2: 1 mole = 6.03 x 1023 particles. One mole of any element has a mass in grams that is equal to its atomic number, and has exactly 6.02 x 1023 atoms - however because the atoms of each element have different sizes and weights, then the volume that each one occupies is different.
Credits to
https://scienceline.ucsb.edu/getkey.php?key=274
Dehydration of Alcohols yield Alkenes. Depending upon the starting material (alcohols) different alkenes are being formed either by following saytzeff rule or Hoffman rule. In case of Cyclopentanol only one alkene is produced (i.e. Cyclopentene) as shown below.