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Naddika [18.5K]
2 years ago
8

A local barista serves coffee at 85°C. You add ice to the coffee to cool it to 55°C. Assume that an ice cube is 24 g and -18.5°C

. How many ice cubes would you need to add to your 355 mL cup of coffee to bring it to 55°C? The specific heat of ice is 2.05 J/g°C, the specific heat of water is 4.184 J/g°C, and the specific heat of fusion of water is 334 J/g. Remember that an ice cube will need to be warmed to 0°C, will melt, and then the newly melted water will be warmed to 55°C.
Question options:

A) 2
B) 4
C) 3
D) 1
Chemistry
1 answer:
Mama L [17]2 years ago
3 0
B)4 ghhhhhhjjjyuuhhdddghhhjj’
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Answer:

Explanation:

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7 .

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Ratio of weight of Ti and O

= 1.916 : 1.28

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2 years ago
A sodium hydroxide solution is made by mixing 8.70 g NaOH with 100 g of water. The resulting solution has a density of 1.087 g/m
Ahat [919]

Answer:

Mass fraction = 0.08004

Mole fraction = 0.0377

Explanation:

Given, Mass of NaOH = 8.70 g

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Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{8.70\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 0.2175\ mol

Given, Mass of water = 100 g

Molar mass of water = 18.0153 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

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Moles= \frac{100\ g}{18.0153\ g/mol}

Moles\ of\ water= 5.5508\ mol

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Mole\ fraction\ of\ NaOH=\frac {n_{NaOH}}{n_{NaOH}+n_{water}}

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Answer:

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Explanation:

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