Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer: 10 - 2√21
Step-by-step explanation: I simplified your question by using an online calculator. :)
Answer:
Hey there!
We can solve this by multiplying 0.3 by 546, which is about 164.
Hope this helps :)
<span>when p = -24 and q = 4. p/2q= -24/8 = -3 </span>
Answer:
I think it would be 350$
Step-by-step explanation:
ok so you have to buy 10 shirts so you need to set up your problem which would be 10(12+8+15)
Then you would have to actually distribute which would give you 120+80+150
Finally you just add all of your numbers together which would be 350$