SOLVE FOR BOTH K's PLS

If 15 actuators have failed today, what is the probability that a) at least 10 are repairable? b) from 3 to 8 are repairable? c)

Ann [662]

The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.

According to the statement

we have given that If 15 actuators have failed and we have to find the probabilities on some conditions.

we know that the formula of probabilities is

probability = possible outcomes / total outcomes

So,

at least 10 are repairable = 1 - (10 are not repairable)

at least 10 are repairable = 1 - 10/15

at least 10 are repairable = (15 - 10)/15

at least 10 are repairable = (5)/15

at least 10 are repairable = 1/3

from 3 to 8 are repairable = 3/15 *8/15

from 3 to 8 are repairable = 1/5 *8/15

exactly 5 are repairable = 5/15

exactly 5 are repairable = 1/3

These are the probabilities of the given conditions.

So, The probabilities of at least 10 are repairable is 1/3. and probabilities of from 3 to 8 are repairable is 1/5*8/15 and probabilities of exactly 5 are repairable is 1/3.

Learn more about PROBABILITIES here brainly.com/question/25870256

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6 0

1 year ago

Julie says I added three odd numbers and my answer was 50 explain why Julie cannot be correct

ANTONII [103]

Julie cannot be right. That's because if you add three odd numbers together, <em>you always get an odd number. </em>The number 50 is an Even number.

Let's try adding 3 odd numbers together a couple of times...
3 + 3 + 3 = 9
5 + 1 + 5 = 11
7 + 3 + 5 = 15
We tried 3 examples, we could not get any even number. So, Julie's claim is wrong.