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maw [93]
3 years ago
12

10) Suppose you have a transparent material that is more dense than glass. How would the light ray be

Physics
1 answer:
Crank3 years ago
5 0

According to the law of reflection, When a ray of light passes from rarer medium to denser medium , it bends towards the normal. So, if there is a transparent material that is more dense than glass then the ray of light will bend towards the normal. The direction of light through the medium is predicted by Snell's Law. According to the Snell's law:

n₁ sin θ₁ = n₂ sin θ₂

Where n₁ is the refractive index of the first medium

n₂ is the refractive index of second medium.

θ₁ and θ₂ are the angle of incidence of light in medium 1 and medium 2

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How is an anion formed?
Trava [24]

Answer:

Cations (positively-charged ions) and anions (negatively-charged ions) are formed when a metal loses electrons, and a nonmetal gains those electrons. The electrostatic attraction between the positives and negatives brings the particles together and creates an ionic compound, such as sodium chloride.

Explanation:

7 0
4 years ago
Read 2 more answers
A person with a remote mountain cabin plans to install her own hydroelectric plant. A nearby stream is 3.00 m wide and 0.500 m d
Lubov Fominskaja [6]

Answer:

The power she can generate is 185.22 KW.

Explanation:

<h3><u>DATA</u></h3>

3.00m wide and 0.500m deep.

Cross sectional area = 1.500m^2

Velocity = 1.35m/s

Volumetric flow rate = Av = 18.00m^3/s

Mass flow rate = 18,000kg/s

Height = 4.20m

25.0% efficiency

<h3><u> FORMULA:</u></h3>

P = dE / dt * eff

<h3><u>SOLUTION:</u></h3>

18,000kg/s (9.8m/s^2) (4.20m) (25%) = 185,220 watts

= 185 kw

6 0
3 years ago
A 615.00 kg race car is uniformly traveling around a circular race track. It takes the race car 20.00 seconds to do one lap arou
koban [17]

Answer:

The value is  f  =  0.05 \ Hz

Explanation:

From the question we are told that

     The mass of the car is  m  =  615 \  kg

      The period of the circular motion is  T  =  20 \  s

      The radius  is r =  80 \  m/s

Generally the frequency of the circular motion is  

       f  =   \frac{1}{T }

=>    f  =   \frac{1}{ 20  }

=>    f  =  0.05 \ Hz

3 0
3 years ago
The diameter of a copper atom is approximately 2.28e-10 m. The massof one mole of copper is 64 grams. Assume that the atoms area
KIM [24]

1) Mass of one copper atom: 1.063\cdot 10^{-22} kg

2) There are 9.33\cdot 10^{24} atoms in the cube

3) Mass of the cubical block: 992 kg

Explanation:

1)

We are told here that the mass of one mole of copper is

M=64 g

for

n=1 mol (number of moles)

We also know that the number of atoms inside 1 mole of substance is equal to Avogadro number:

N_A = 6.022\cdot 10^{23}

This means that N_A atoms of copper have a mass of M = 64 g. Therefore, we can find the mass of one copper atom by dividing the total mass by the avogadro number:

m=\frac{M}{N_A}=\frac{64}{6.022\cdot 10^{23}}=1.063\cdot 10^{-22} kg

2)

We are told that the diameter of a copper atom is

d=2.28\cdot 10^{-10} m

We can assume that the atoms are arranged in a cube, and that they are all attached to each other; so the side of the cube can be written as size of one atom multiplied by the number of atom per side:

L=Nd

where

N is the number of atoms (rows) in one side of the cube

Since the side of the cube is

L = 4.8 cm = 0.048 m

We find N:

N=\frac{L}{d}=\frac{0.048}{2.28\cdot 10^{-10}}=2.11\cdot 10^8

This is the number of atom rows per side; therefore, the total number of atoms in the cube is

N^3=(2.11\cdot 10^8)^3=9.33\cdot 10^{24}

3)

The total mass of the cubical block of copper will be given by the mass of one atom of copper multiplied by the total number of atoms, so:

M= N^3 m

where:

N^3 = 9.33\cdot 10^{24} is the number of atoms in the cube

m=1.063\cdot 10^{-22} kg is the mass of one atom

Therefore, substituting, we find:

M=(9.33\cdot 10^{24})(1.063\cdot 10^{-22})=992 kg

So, the mass of the cubical block is 992 kg.

Learn more about mass and density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

3 0
3 years ago
A torque of 0.77 N⋅m is applied to a bicycle wheel of radius 30 cm and mass 0.70 kg
Naddik [55]

Answer:

α = τ/I = 0.77 / (0.70(0.30²)) = 12.22222... = 12 rad/s²

Explanation:

4 0
3 years ago
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