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mr_godi [17]
2 years ago
8

21. a. Describe why there is a difference in bond angles between H20 and CH4. (2 pts)

Chemistry
1 answer:
statuscvo [17]2 years ago
4 0

Answer:

The H—C—H bond angle in methane is the tetrahedral angle, 109.5°. This angle is obtained when all four pairs of outer electrons repel each other equally. The bond angles in water is less than 109.5° because of the stronger repulsion by their lone pairs of electrons.

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A small can rolled 2 meters in 2 hours.​
inn [45]
2.187 is the answer to this question
7 0
2 years ago
A gas that effuses through a porous cylinder 1.87 times faster than chlorine gas. what is the molar mass and identity.
Rufina [12.5K]
From the Graham's law of effusion;
R1/R2 = √MM2/√MM1
Molar mass of chlorine gas is 71
Therefore;
1.87= √ 71 /√mm1
= 1.87² = 71/mm1 
mm1 = 71/1.87²
         = 71/3.4969
         = 20.3
Thus, the molar mass of the other gas is 20.3 , and i think the gas is neon
6 0
3 years ago
Resources that are not able to be reproduced as quickly as they are used are called _____.
Maurinko [17]

Answer:

C) non renewable resources

Explanation:

These are resources such as oil that are formed over a long period of time but are consumed very quickly.

8 0
3 years ago
When 100 mL of 1.0 M Na3PO4 is mixed with 100 mL of 1.0 M AgNO3, a yellow precipitate forms and [Ag ] becomes negligibly small.
lana [24]

Answer:

Na3PO4 + 3AgNO3 -------> Ag3PO4 + 3NaNO3

In which [Ag+] in negligibly small and the concentration of each reactant is 1.0 M

The answer is A)  PO43- < NO3- < Na+

Explanation:

Ag+ is removed from the solution just like PO43-, so there are just 2 possible answers at this point: a or b. Then we can notice that Na3PO4 releases 3 moles of Na+ and just 1 mole of NO3-

We have 100mL of each reactant with the same concentration for both (1.0 M) so:

(0.1)(1)(3)= 0.3 mol Na+

(0.1)(1)= 0.1 mol NO3-

so PO43- < NO3- < Na+

5 0
3 years ago
Mercury has a mass density of 13.54 g/ml . how many milliliters would 100. grams occupy
frosja888 [35]
<span>7.39 ml For this problem, simply divide the mass of mercury you have by it's density. 100 g / 13.54 g/ml = 7.3855 ml Since we only have 3 significant digits in 100., you need to round the result to 3 significant digits. So 7.3855 ml = 7.39 ml</span>
6 0
3 years ago
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