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3 years ago

Solve for V 6+2(4v-5)=-2(7v-4)+7v

2 answers:

tatiyna3 years ago

6 0

6+2(4v-5)=-2(7v-4)+7v
6+8v-10 = -14v+8 +7v
-4+8v = -7v +8
-4+4+8v = -7v + 8 + 4
8v = -7v + 12
8v+7v =-7v+7v+12
15v =12
15v/15 = 12/15
v = 4/5

check

6+2(4(4/5)-5)=-2(7(4/5)-4)+7(4/5)
6 +2(3.2-5) = -2(5.6-4)+5.6
6+2(-1.8) = -2(1.6)+5.6
6+-3.6=-3.2+5.6
2.4=2.4

klasskru [66]3 years ago

5 0

6+2(4v-5)=-2(7v-4)+7v
6 + 8v - 10 = -14v + 8 +7v
8v - 4 = -7v + 8
15v = 12
v = 12/15
v = 4/5

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When Vince does 14 push-ups and 12 sit-ups, it takes a total of 52 seconds. In comparison, he needs 48 seconds to do 12 push-ups

marshall27 [118]

Answer:

it takes 2 seconds to do one situp

it takes 2 seconds to do one pushup

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to do 12 situps it takes 24 seconds

to do 12 pushups, it takes 24 seconds

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hope this helps :)

Step-by-step explanation:

14x + 12y = 52

12x + 12y = 48

^^^ this is an inequality that we can make.

x stands for pushups

y stands for situps

if we subtract the second equation from the first, we get

2x = 4

x = 2

now we can place x in one of the equations to solve for y

12(2)+12y=48

24 + 12y = 48

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2 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

The perimeter of a rectangle is about 13.9 cm. If you double the width of the rectangle the perimeter is about 17.8 cm. Find the

fredd [130]

Answer:

5cm by 1.95cm

Step-by-step explanation:

Let the length of the rectangle be x

Let the width be y

Perimeter of a rectangle = 2x + 2y

If the initial perimeter of a rectangle is about 13.9 cm, then;

13.9 = 2x + 2y ..... 1

If when the width is double the perimeter is 17.8cm, then;

17.8 = 2x + 4y ..... 2

Subtract 1 from 2;

13.9 - 17.8 = 2y - 4y

- 3.9 = -2y

y = 3.9/2

y = 1.95 cm

Substitute y = 1.95 into 1 to get x;

From 1;

13.9 = 2x + 2y

13.9 = 2x + 2(1.95)

13.9 = 2x + 3.9

2x = 13.9-3.9

2x = 10

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3 years ago

What are different representations of a function?

Soloha48 [4]

Answer:

a function can be represented by a bike

Step-by-step explanation:

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3 years ago

A car is being driven at a rate of 40 ft/sec when the brakes are applied. The car decelerates at a constant rate of 10 ft/sec2.

IRISSAK [1]

Answer:

80 feet

Step-by-step explanation:

Given:

Initial speed of the car ( $v_0$ ) = 40 ft/sec

Deceleration of the car ( $\frac{dv}{dt}$ ) = -10 ft/sec²

Final speed of the car ( $v_x$ ) = 0 ft/sec

Let the distance traveled by the car be 'x' at any time 't'. Let 'v' be the velocity at any time 't'.

Now, deceleration means rate of decrease of velocity.

So, $\frac{dv}{dt}=-10\ ft/sec^2$

Negative sign means the velocity is decreasing with time.

Now, $\frac{dv}{dt}=\frac{dv}{dx}(\frac{dx}{dt})$ using chain rule of differentiation. Therefore,

$\frac{dv}{dx}\cdot\frac{dx}{dt}= -10\\\\But\ \frac{dx}{dt}=v.\ So,\\\\v\frac{dv}{dx}=-10\\\\vdv=-10dx$

Integrating both sides under the limit 40 to 0 for 'v' and 0 to 'x' for 'x'. This gives,

$\int\limits^0_{40} {v} \, dv=\int\limits^x_0 {-10} \, dx\\\\\left [ \frac{v^2}{2} \right ]_{40}^{0}=-10x\\\\-10x=\frac{0}{2}-\frac{1600}{2}\\\\10x=800\\\\x=\frac{800}{10}=80\ ft$

Therefore, the car travels a distance of 80 feet before stopping.

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3 years ago