Carbon can form a maximum of 4 covalent bonds because it has 4 valence electrons i.e. 4 outer electrons.
Molarity is the number
of moles of solute in one liter of the solution. Mathematically, M = n/V. Where
Molarity of the solution is M, Number of moles of solute is n, and volume of the
solution is V.
Calculate the mass in
1000 mL of the solution. Density of acetic acid is 1.00 g/mL.
Density = 1.00 g/mL. 1.0
mL has mass 1.00 g. 1000.0 mL has mass = (1000.0 mL/ 1.0 mL) * 1.00 g = 1000.0
g. hence, the mass in 1000.0 mL of the solution if 1000.0 g.
Calculate the mass
contained of 5.00 % acetic acid as follows: 5.00 % of 1040 g = (5.00 / 100) *
1000.0 g = 50.0 g. Hence, the mass contained of 5.00 % acetic acid is
50.0 g.
Calculate the number of moles of acetic acid. Number of
moles = Mass / Molar mass = 50.0 g / 60.0 g/mol = 0.8333 mol. Hence, the number
of moles of acetic acid is 0.8333 mol.
Calculate the molarity of the solution, M = n / V = 0.8333
mol / 1.0 L = 0.8333 M
Therefore, the molarity of the solution if 0.8333 M
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Answer:
1.40 moles.
Explanation:
The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -
In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.
Since, 2 moles of is formed by 4 moles of
So, for 1.8 moles of amount of required moles of =
In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.
Since, 2 moles of is formed by 5 moles of oxygen
So, for 1.40 moles of moles of required =
Thus as of now we have 3.60 moles of and 3.50 moles of .
As in the reaction of formation of , oxygen is the limiting reagent.
So the moles of formed by the 3.50 moles of oxygen will be
= = 1.40 moles.
Answer:
Egg is heterogeneous.
Ranch Dressing is heterogeneous
Windex is homogeneous.
Answer:
Algo importante sobre el balance de una reacción química es la ley de la conservación de la masa que establece que la masa no se crea ni se destruye sólo se transforma de modo que en una reacción química la suma de la masa de los reactivos debe ser igual a la suma de la masa de los productos.
Por ejemplo: La fermentación de la glucosa es una reacción química balanceada que da como resultado etanol y dióxido de carbono.
C₆H₁₂O₆ → 2C₂H₆O +2CO₂
Calculando la masa de los reactivos y productos, se debe cumplir la ley de la conservación de la masa:
C₆H₁₂O₆= 6*12+12*1+6*16=180 g/mol
C₂H₆O= 2*12+6*1+16=46 g/mol
CO₂=12+2*16=44 g/mol
C₆H₁₂O₆ → 2C₂H₆O + 2CO₂
180 g/mol = 2*46 g/mol + 2*44 g/mol
180 g/mol = 92 g/mol + 88 g/mol
180 g/mol = 180 g/mol