Answer: 5.12x10∧-4N
Explanation:
Force = I B L
L = 6.4m
Let Current (I) I₁ = I₂= 14A
Distance of the wire = 42cm = 0.42m
BUT
B = μ₀I / 2πr
=(2X10∧-7 X 12) / 0.42
B =5.714×10∧-6T
Force = I B L
Force = 14x [5.714×10-6]×6.4
Force = 5.12x10∧-4N
1) C
2) 2[A]
3) 2[A]
4) a less bright (?)
b 1 [A]
c 1 [A]
5) brighter (?)
6)
a 0.8 (if it is the one on the right of 6)
b 0.4 [A]
c 0.4 [A]
d depends on where you place it.
7)
a place it next to X, right or left
b place it just after the source
(?) = not sure
If you have more questions ask.
I would go with C because all the rest of the answer are sitting on something.
