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2 years ago

How does the composition of a comet compare with that of the Sun?.

1 answer:

4 0

Comets are frozen leftovers from the formation of the solar system composed of dust, rock, and ice. Sun is a nearly perfect ball of hot plasma, heated to incandescence in its center by nuclear fusion reactions. Comets can be compared to the sun on the basis of size, composition, and position in the solar system.

The Sun is the central star of our Solar System. It's a nearly perfect ball of hot plasma, heated to incandescence in its center by nuclear fusion reactions.

Sun emits energy mostly as visible light, ultraviolet light, and infrared radiation. It is the most vital source of energy for life on Earth.

<h3>What are comets?</h3>

A comet is a tiny entity circling the Sun that contains a significant amount of volatile ices, which includes entrained dust particles.

The comet forms two tails, one of ionized molecules and radicals and the other of dust, as dust and gas in the coma flow freely into space.

Comets are frozen remnants of the solar system's origin, made of dust, rock, and ice.

They range in size from a few miles to tens of miles across, but as they get closer to the Sun, they heat up and spew gases and dust into a flaming head the size of a jet.

Hence comets can be compared to the sun on the basis of size, composition, and position in the solar system.

To know more about the comets refer to the link;

brainly.com/question/9656759

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Why does the moon lack an atmosphere?

vesna_86 [32]

Because when it had any, the warmth of the sun heated the atmosphere to the point where the average speed of the gas molecules exceeded the escape velocity for a body with the moon's mass and size. So, little by little, they escaped.

8 0

3 years ago

How does the planet Venus look to a person standing on the Earth?

Tema [17]

Answer:

A person would look like an ant if a human was standing next to Venus

Explanation:

4 0

3 years ago

Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground

Setler79 [48]

They will both hit the ground at the same time because gravitational acceleration for all objects is the same.

6 0

3 years ago

Tectonic plates are large segments of the earth's crust that move slowly. Suppose one such plate has an average speed of 6.0 cm

faltersainse [42]

Answer:

1.35×10⁻⁷ m

37.278 mi/My

Explanation:

Speed of the tectonic plate= 6 cm/yr

Converting to seconds

$6=\frac{6}{365.25\times 24\times 60\times 60}$

So in one second it will move

$\frac{6}{365.25\times 24\times 60\times 60}$

In 71 seconds

$71\times \frac{6}{365.25\times 24\times 60\times 60}=1.35\times 10^{-5}\ cm$

The tectonic plate will move 1.35×10⁻⁵ cm or 1.35×10⁻⁷ m

Convert to mi/My

1 cm = 6.213×10⁻⁶ mi

1 M = 10⁶ years

$6\times 6.213\times 10^{-6}\times 10^6=37.278\ mi/My$

Speed of the tectonic plate is 37.278 mi/My

7 0

3 years ago

A carnival game consists of a two masses on a curved frictionless track, as pictured below. The player pushes the larger object

Harman [31]

Answer:

v₁₀ = 1.90 m / s

Explanation:

In this exercise we are given the maximum height data, with energy we can know how fast the body came out

Final mechanical energy, maximum height

$Em_{f}$ = U = m g h

Initial mechanical energy, in the lower part of the track

Em₀ = K = ½ m v²

Em= $Em_{f}$

½ m v² = m g h

v = √ 2gh

Now we can use the moment to find the speed with which objects collide

The large object has a mass M = 5.41 kg a velocity starts v₁₀, the small object has a mass m = 1.68 kg an initial velocity of zero v₂₀ = 0 and final velocity v

Initial before the crash

p₀ = M v₁₀ + 0

Final after the crash

$p_{f}$ = M v1f + m v

p₀ = $p_{f}$

M v₁₀ = M $v_{1f}$ + m v

As the shock is elastic the kinetic energy is conserved

K₀ = $K_{f}$

½ M v₁₀² = ½ M $v_{1f}$ ² + ½ m v²

Let's write the system of equations

M v₁₀ = M $v_{1f}$ + m v

M v1₁₀² = M $v_{1f}$ ² + m v²

We cleared v1f in the first we replaced in the second

$v_{1f}$ = (M v₁₀ - mv) / M

M v₁₀² = M (M v₁₀ - mv)² / M² + m v²

M v₁₀² = 1 / M (M² v₁₀² - 2mM v v₁₀ + m² v²) +m v²

v₁₀² (M - M) + 2 m v v₁₀ - v² (m2 + m) / M = 0

2 m v₁₀ - v (m + 1) m/ M = 0

v₁₀ = v (m +1) / (2M)

Let's substitute the value of v

v1₁₀= √ (2gh) (m +1) / (2M)

Let's calculate

v₁₀ = √ (2 9.8 3) (1+ 1.68) / (2 5.41)

V₁₀ = 7.668 (2.68) / 10.82

v₁₀ = 1.90 m / s

5 0

3 years ago