All categories

3 years ago

What could result from regular participation in sports and exercise

Physics

1 answer:

shusha [124]3 years ago

5 0

Common health issues that can be positively affected, prevented or controlled by exercise.

You might be interested in

The image formed by the pinhole camera is smaller than that of the object true or false

Zina [86]

Answer: True? since it has a small hole it would depend on how far away the camera is to the object.

4 0

2 years ago

A solid yellow line on your side of the center stripe means pass with care. A. True B. False

oee [108]

Answer:

Explanation:

a straight yellow is a no pass zone

7 0

2 years ago

In which phase is the full illuminated face of the Moon visible on Earth? A) New moon Eliminate B) Full moon C) Waning gibbous D

Nitella [24]

Full moon

New cant be seen

Gibbous is 3/4

Crescent is 1/4

4 0

2 years ago

Which of the following is a fossil fuel? A. Coal B. Wind energy C. Biomass energy

almond37 [142]

A. Coal

is the correct answer

5 0

2 years ago

Read 2 more answers

The following table lists the work functions of a few commonmetals, measured in electron volts.

steposvetlana [31]

Answer:

Lithium

Explanation:

The equation for the photoelectric effect is

$\frac{hc}{\lambda}= \phi + K_{max}$

where

$\frac{hc}{\lambda}$ is the energy of the incident photon, with

h being the Planck constant

c is the speed of light

$\lambda$ is the wavelength of the photon

$\phi$ is the work function of the metal (the minimum energy needed to extract the photoelectron from the metal)

$K_{max}$ is the maximum kinetic energy of the emitted photoelectrons

In this problem, we have

$\lambda= 190 nm = 1.9\cdot 10^{-7}m$ is the wavelength of the incident photon

$K_{max}=4.0 eV$ is the maximum kinetic energy of the electrons

First of all we can find the energy of the incident photon

$E=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{1.90\cdot 10^{-7} m}=1.05\cdot 10^{-18} J$

Converting into electronvolts,

$E=\frac{1.05\cdot 10^{-18} J}{1.6\cdot 10^{-19} J/eV}=6.6 eV$

So now we can re-arrange the equation of the photoelectric effect to find the work function of the metal

$\phi = E-K_{max}=6.6 eV - 4.0 eV=2.6 eV$

So the metal is most likely Lithium, which has a work function of 2.5 eV.

3 0

3 years ago