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3 years ago

What could result from regular participation in sports and exercise

Physics

1 answer:

shusha [124]3 years ago

5 0

Common health issues that can be positively affected, prevented or controlled by exercise.

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A_ is a cut made through the wood

Cloud [144]

Answer:

i believe the answer is B only because i looked it up on g00gle so take what i say with a GRAIN of salt all puns intended

Explanation:

6 0

3 years ago

Read 2 more answers

A positive charge is fixed at point (−4,−3) and a negative charge − is fixed at point (−4,0). Determine the net electric force ⃗

Masteriza [31]

The net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).

<h3>Net electric force on the charges</h3>

The net electric force on the charges is calculated as follows;

F = kq₁q₂/r²

where;

k is coulomb's constant
q₁ and q₂ are the charges
r is the distance between the charges

<h3>Distance between the charges</h3>

$|r| = \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2} \\\\|r| = \sqrt{(-4--4)^2+ (0--3)^2} \\\\|r| = \sqrt{(0)^2 + (3)^2} \\\\|r| = 3 \ units$

$F_{net} = \frac{kq_1q_2}{3^2} \\\\F_{net} = \frac{1}{9} (kq_1q_2) , \ N$

Thus, the net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).

Learn more about electric force here: brainly.com/question/17692887

#SPJ1

3 0

2 years ago

What type of pressure is transmitted by fluids

Evgesh-ka [11]

Cerebrospinal fluid or Hydrocephalus

5 0

3 years ago

Show all work please I am stuck

MissTica

Answer:

Explanation:

1 meter = 39.37 inches

meters x inches/meters = inches

6.23x10^-4 m x 39.37 in./m=0.245...=2.45x10^-2

5 0

2 years ago

A pilot heads his jet due east. The jet has a speed of 475 mi/h relative to the air. The wind is blowing due north with a speed

oksian1 [2.3K]

Explanation:

a. The velocity of the wind as a vector in component form will be represented as v vector:

$v=30j$

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

$u=475i$

c. The true velocity of the jet as a vector will be represented as w:

$w=u+v$

$w=475i+30j$

d. The true speed of the jet will be calculated as:

$IwI=\sqrt{(475)^2+(30)^2}$

$IwI=\sqrt{225625+900}$

$IwI=\sqrt{226525}$

$IwI=476 mi/h$

e. The direction of the jet will be:

$tita=tan^{-1}\frac{30}{475}$

$tita=tan^{-1}(0.0632)$

$tita=3.62degrees,or,N86.38degreesS$

7 0

3 years ago