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3 years ago

Help with physics projectile motion

Physics

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Answer:

10.4 m/s

Explanation:

First, find the time it takes for the projectile to fall 6 m.

Given:

y₀ = 6 m

y = 0 m

v₀ = 0 m/s

a = -9.8 m/s²

Find: t

y = y₀ + v₀ t + ½ at²

(0 m) = (6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.11 s

Now find the horizontal position of the target after that time:

Given:

x₀ = 6 m

v₀ = 5 m/s

a = 0 m/s²

t = 1.11 s

Find: x

x = x₀ + v₀ t + ½ at²

x = (6 m) + (5 m/s) (1.11 s) + ½ (0 m/s²) (1.11 s)²

x = 11.5 m

Finally, find the launch velocity needed to travel that distance in that time.

Given:

x₀ = 0 m

x = 11.5 m

t = 1.11 s

a = 0 m/s²

Find: v₀

(11.5 m) = (0 m) + v₀ (1.11 s) + ½ (0 m/s²) (1.11 s)²

v₀ = 10.4 m/s

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To solve this problem it is necessary to apply the concepts related to the principle of superposition and the equations of destructive and constructive interference.

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Re-arrange to find the distance between the slits we have,

$d = \frac{m\lambda}{sin\theta }$

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Therefore the number of lines per millimeter would be given as

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3 years ago

What is the average power supplied by a 60.0 kg secretary running up a flight of stairs rising vertically 4.0 m in 4.2 s?

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Answer:

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Mass of proton $m=1.67\times10^{-27}\ kg$

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Put the value into the formula

$K.E=\dfrac{1}{2}\times1.67\times10^{-27}\times(9.00\times10^{7})^2$

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Using formula of kinetic energy

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Learn more about force and work:brainly.com/question/758238

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2 years ago

Help with physics projectile motion​

Help with physics projectile motion