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Zielflug [23.3K]

2 years ago

11

A train left for Miami, and 6 hours later, a car traveling 79 mph tried catching up to the train. After 7 hours, the car caught

up. What was the train's average speed?

1 answer:

nikdorinn [45]2 years ago

5 0

Answer: 121 mph

Step-by-step explanation: First, I did 6 x 7, and I got 42. Then I did 42 + 79, and I got 121 mph as my answer.

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I’m doing volume of rectangular prisms

Rom4ik [11]

sorry wait please delete my answer I realized my mistake!

5 0

3 years ago

Read 2 more answers

Estimate how much 10.25 and 30.5

Elza [17]

I don't really get what you are asking for. Can you clarify it?

5 0

2 years ago

Read 2 more answers

Z to the power of 2 =1

stiv31 [10]

That would be written as:

$z^{2} = 1$

And the step-by-step equation would be:

$z^{2} = 1$ → we take the 2 to the right side of the equation and do the IO*

$z = \sqrt{1}$ →we solve for $\sqrt{1}$

$z = 1$ → final answer

*Ps - IO is not an existing term and stands for inverse operation. In this case, because when we take to 2 to the right side of the equation (the 2 is a power) it'll have to turn into a square root (because exponents and roots are inverse operations)

Hope it helped,

BioTeacher101

3 0

3 years ago

Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona

andrey2020 [161]

Answer:

a. v.v' = v₁v₂ - v₁v₂ = 0 b. (20, -21)/29 and (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' = (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

= v₁v₂ - v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0

2 years ago

Garth buys 24 kilograms of candy. He then repacks the candy into small bags of 34 kilogram each. How many bags does he pack? A.

LenaWriter [7]

<u>Corrected Question</u>

Garth buys 24 kilograms of candy. He then repacks the candy into small bags of 3/4 kilogram each. How many bags does he pack?

Answer:

C. 32 bags

Step-by-step explanation:

Total Weight of Bag bought =24 kilograms

Since Garth wants to repack the candy into small bags of 3/4 kg, we simply divide 24 by 3/4 to obtain the number of small bags.

$24 \div \dfrac{3}{4}= 24 X \dfrac{4}{3}\\=32$

There will be 32 small bags of 3/4 kg.

The correct option is C.

6 0

3 years ago