1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Norma-Jean [14]
3 years ago
7

A car accident occurs around midnight on the night of a full moon. The driver at fault claims he was blinded momentarily by the

Moon rising on the eastern horizon. Should the police believe him?
Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

No

Explanation:

It is well explained in the question itself that the accident took place at mid night on a full moon.

At mid night , the moon will be high on sky, it will not be rising.

So the statement of driver is false as there will not be any moon rising on eastern horizon when moon is already at the highest on sky.

This shows he is certainly lying and police should not believe him.

Flura [38]3 years ago
5 0

At full moon the moon is directly opposite the sun as viewed from earth.

That is, when the sun is setting the moon is rising. At midnight a full

moon would be directly overhead.

You might be interested in
A circular cylinder has a diameter of 3.0 cm and a mass of 25 g. It floats in water with its long axis perpendicular to the wate
Vilka [71]

Answer:

   f = 5.3 Hz

Explanation:

To solve this problem, let's find the equation that describes the process, using Newton's second law

        ∑ F = ma

where the acceleration is

         a = \frac{d^2 y}{dt^2 }

        B- W = m \frac{d^2 y}{dt^2 }

To solve this problem we create a change in the reference system, we place the zero at the equilibrium point

           B = W

In this frame of reference, the variable y'  when it is oscillating is positive and negative, therefore Newton's equation remains

         B’= m \frac{d^2 y'}{dt^2 }

           

the thrust is given by the Archimedes relation

         B = ρ_liquid g V_liquid

     

the volume is

        V = π r² y'

     

we substitute

          - ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }

          \frac{d^2 y'}{dt^2} + \rho_liquid \ g \ \pi  r^2/m ) y' \ =0

this differential equation has a solution of type

         y = A cos (wt + Ф)

where

         w² = ρ_liquid g π r² /m

angular velocity and frequency are related

         w = 2π f

         

we substitute

          4π² f² = ρ_liquid g π r² / m

          f = \frac{1}{2\pi } \ \sqrt{ \frac{ \rho_{liquid} \  \pi  r^2 \ g}{m } }

calculate

         f = \frac{1}{2 \pi }  \sqrt{ \frac{ 1000 \ \pi  \ 0.03^2 \ 9.8 }{0.025}  }

         f = 5.3 Hz

6 0
2 years ago
A student sits on a pivoted stool while holding a pair of weights. The stool is free to rotate about a vertical axis with neglig
Blababa [14]

Answer:

<u>Please Mark As Brainliest!!</u>

a) 4.99 rad/sec b) 6.24 rad/sec c) 7.03 J

Explanation:

a)  If the student completes one turn in 1.26 sec, this is called the period of the movement.

If we take into account that the angle rotated during one turn is 2π rads, by definition of angular velocity, we can get this value as follows:

ω = Δθ / Δt = 2*π rad / 1.26 seg = 4.99 rad/sec.

b) As no external torques are acting on the system, the total angular momentum must be conserved, so we can write the following equation:

Li = Lf   ⇒  I₁ * ω₁  = I₂* ω₂

So, we can solve for ω₂, as follows:

ω₂ = (I₁ * ω₁) / I₂ = 6.24 rad/sec

c) Appying the work-energy theorem, we know that the work done by the student, must be equal to the change in the kinetic energy, which in this case is only rotational, so we can write:

W = 1/2 I₂* ω₂² - 1/2 I₁ ω₁²

W =1/2 ((2.25 kg.m² * (6.24)²) (rad/sec)² - (1.8 kg.m²* (4.99)²) (rad/sec)²)  

W = 7.03 J

4 0
2 years ago
Give one example of something you use or make at home that is an example of solubility.
Nana76 [90]

Answer:

Salt can dissolve in water making it an excellent soluble for water

5 0
3 years ago
Read 2 more answers
An experiment yielded the above temperature and time information. what is the freezing point of the material in this experiment
Dmitry [639]
The answer is 0 degrees Celsius (0°C). It will be where the line flat lines the first time.  The second time would be the boiling point.  An experiment yielded the above temperature and time information. The freezing point of the material in this experiment if the material is a solid at time zero is 0 degrees Celsius (0°C) .
7 0
3 years ago
Two charged particles separated by a distance of = 3 and experienced electrostatic forces of = 60 . What would be this force if
klemol [59]

Answer: 539.4 N

Explanation:

Let's begin by explaining that Coulomb's Law establishes the following:  

"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them"

What is written above is expressed mathematically as follows:

F_{E}= K\frac{q_{1}.q_{2}}{d^{2}} (1)

Where:

F_{E}=60 N  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1} and q_{2} are the electric charges

d=3 m is the separation distance between the charges  

Then:

60 N= 8.99(10)^{9} Nm^{2}/C^{2}\frac{q_{1}.q_{2}}{(3 m)^{2}} (2)

Isolating q_{1} and q_{2}:

q_{1}q_{2}=6(10)^{-8} C^{2} (3)

Now, if we keep the same charges but we decrease the distance to d_{1}=1 m, (1) is rewritten as:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{6(10)^{-8} C^{2}}{(1 m)^{2}} (4)

Then, the new electrostatic force will be:

F_{E}= 539.4 N (5) As we can see, the electrostatic force is increased when we decrease the distance between the charges.

4 0
3 years ago
Other questions:
  • •1 if a saturn v rocket with an apollo spacecraft attached had a combined mass of 2.9 × 105 kg and reached a speed of 11.2 km/s,
    12·1 answer
  • A 3.00-kg box that is several hundred meters above the earth’s surface is suspended from the end of a short vertical rope of neg
    13·1 answer
  • Help me I need help anyone
    11·2 answers
  • Which of the following is not true about a vertical component? The vertical component of a projectile changes due to gravity. Th
    8·2 answers
  • A 9.0 cm object is 3.0 cm from a lens, which has a focal length of –12.0 cm.
    15·2 answers
  • This graph indicates that the acceleration between 2.00 and 4.00 seconds is the same as that between 12.00 and 14.00 seconds.
    9·1 answer
  • Please help me with this assignment!
    14·2 answers
  • Which model best represents a pattern
    10·2 answers
  • Calcula qué tan lejos está Saturno del Sol, sabiendo que la luz solar necesita una hora y veinte segundos para llegar a Saturno.
    9·1 answer
  • What is the relation between liquid pressure and density of liquid<br><br><br>plzz fast ​
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!