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Norma-Jean [14]
3 years ago
7

A car accident occurs around midnight on the night of a full moon. The driver at fault claims he was blinded momentarily by the

Moon rising on the eastern horizon. Should the police believe him?
Physics
2 answers:
elena-14-01-66 [18.8K]3 years ago
7 0

Answer:

No

Explanation:

It is well explained in the question itself that the accident took place at mid night on a full moon.

At mid night , the moon will be high on sky, it will not be rising.

So the statement of driver is false as there will not be any moon rising on eastern horizon when moon is already at the highest on sky.

This shows he is certainly lying and police should not believe him.

Flura [38]3 years ago
5 0

At full moon the moon is directly opposite the sun as viewed from earth.

That is, when the sun is setting the moon is rising. At midnight a full

moon would be directly overhead.

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A its is high and low pressure areas
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An example of a single displacement reaction is
Elden [556K]
Single replacement would be represented by a single element being replaced.

This is shown in answer choice B
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3 years ago
PLEASE HELP 15 POINTS AND BRAINIEST!!!<br> Reporting fake answers
Zolol [24]

Answer:

(3) The period of the satellite is independent of its mass, an increase in the mass of the satellite will not affect its period around the Earth.

(4) he gravitational force between the Sun and Neptune is 6.75 x 10²⁰ N

Explanation:

(3) The period of a satellite is given as;

T = 2\pi \sqrt{\frac{r^3}{GM} }

where;

T is the period of the satellite

M is mass of Earth

r is the radius of the orbit

Thus, the period of the satellite is independent of its mass, an increase in the mass of the satellite will not affect its period around the Earth.

 

(4)

Given;

mass of the ball, m₁ = 1.99 x 10⁴⁰ kg

mass of Neptune, m₂ = 1.03 x 10²⁶ kg

mass of Sun, m₃ = 1.99 x 10³⁰ kg

distance between the Sun and Neptune, r = 4.5 x 10¹² m

The gravitational force between the Sun and Neptune is calculated as;

F_g = \frac{Gm_2m_3}{r^2} \\\\F_g = \frac{6.67\times 10^{-11} \times 1.03 \times 10^{26}\times 1.99\times 10^{30}}{(4.5\times 10^{12})^2} \\\\F_g = 6.751 \times 10^{20} \ N

5 0
3 years ago
An ant can travel approximately 30 meters per minute. How many meters could an ant move in 45 minutes.
Nastasia [14]

Answer:

From what I see, it's saying that every minute, the ant can move 30 meters.  So how many meter would it move in 45 minutes?

30 meters = 1 min

x meters = 45 min

1 min x 45 = 45 min

30 meters x 45 = 1,350 meters

So, I believe the answer would be 1,350 meters.

hope this helps. :>

8 0
3 years ago
The kinetic energy of a moving object is E=12mv2. A 61 kg runner is moving at 10kmh. However, her speedometer is only accurate t
jek_recluse [69]

Answer:

e=3367.2J

%e=1.43%

Explanation:

From the exercise we know two information. The real speed and the experimental measured by the speedometer

v_{r}=10km/h=2.77m/s

Since the speedometer is only accurate to within 0.1km/h the experimental speed is

v_{e}=10km/h-0.1km/h=9.9km/h=2.75m/s

Knowing that we can calculate Kinetic energy for the real and experimental speed

E_{r}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.77m/s)^2=234023J

E_{e}=\frac{1}{2}mv^2=\frac{1}{2}(61000g)(2.75m/s)^2=230656J

Now, the potential error in her calculated kinetic energy is:

e=E_{r}-E_{e}=(234023-230656)J=3367.2J

%e=\frac{E_{r}-E_{e}}{E_{r}}x100=\frac{(234023-230656)J}{234023J}x100=1.43%

4 0
3 years ago
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