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ruslelena [56]
3 years ago
5

The girl makes a microscope with a 3.0 cm focal length objective and a 5.0 cm eyepiece. The microscope tube length is 10 cm. Use

the simple formula to find the expected magnification of this microscope.
(A) 12
(B) 14
(C) 17
(D) 20
(E) 24
Physics
1 answer:
saul85 [17]3 years ago
3 0

To solve this problem we will use the concepts related to Magnification. Magnification is the process of enlarging the apparent size, not physical size, of something. This enlargement is quantified by a calculated number also called "magnification".

The overall magnification of microscope is

M = \frac{Nl}{f_ef_0}

Where

N = Near point

l = distance between the object lens and eye lens

f_0= Focal length

f_e= Focal of eyepiece

Given that the minimum distance at which the eye is able to focus is about 25cm we have that N = 25cm

Replacing,

M = \frac{25*10}{3*5}

M = 16.67\approx 17\\

Therefore the correct answer is C.

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Sulphur

The missing element is sulphur

Here the compound is composed of  element X and chlorine.

it is given,

XCl (6) ----> 6Cl

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it is X and Cl = 100%-13.10%

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  • we discover that we have  0.4086 moles of X when we divide this by six.
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