What is the relation between energy and amplitude of a light wave, if amplitudes a factor in energy?

Do all objects fall at the same rate?and if they do not why?

Tema [17]

No, I heavier object will fall much faster than something lighter than it. This is because it’s more dense and hard so it can cut through the air particles quicker than a lighter object which takes longer to cut through the air and fall

Example:

A rock vs a feather
The rock will fall quicker because it’s more dense and falls straight down and the feather will be slower because it flows slowly down through the air particles

6 0

3 years ago

Will mark brainliest!

MaRussiya [10]

Answer:

Explanation:

Fa - u*m*g = m*a

Fa = u*m*g + m*a

Fa - m*a = u*m*g

u = $\frac{Fa - m*a}{m*g}$

8 0

3 years ago

Mosses don't spread by dispersing seeds; they disperse tiny spores. The spores are so small that they will stay aloft and move w

AnnyKZ [126]

A) 0.3

The initial kinetic energy of the stream of spores is

$K_i = \frac{1}{2}mv^2$

where m is the mass of the spores and v = 3.6 m/s is their initial speed.

The final gravitational potential energy (at the point of maximum height) of the spores is

$U_f = mgh$

where g=9.8 m/s^2 is the acceleration due to gravity and h = 20 cm = 0.20 m is the maximum height.

Therefore, the fraction of kinetic energy converted to final potential energy is

$\frac{U_f}{K_i}=\frac{mgh}{\frac{1}{2}mv^2}=\frac{2gh}{v^2}=\frac{2(9.8 m/s^2)(0.20 m)}{(3.6 m/s)^2}=0.30$

So, about 30% of the initial kinetic energy is converted into potential energy.

B) It has been transformed into thermal energy of the spores and surrounding air

In fact, because of the presence of the air resistance during the motion of the spores, some of the mechanical energy of the spores is "wasted" and converted into thermal energy (heat) of the spores and the surrounding air. Without the air resistance, the mechanical energy would be conserved, and the final potential energy of the spore would be equal to the initial kinetic energy.

3 0

3 years ago

(Another tomato/skyscraper problem.) You are looking out your window in a skyscraper, and again your window is at a height of 45

Ivan

Answer:

1027.2 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 32.2 ft/s

$s=ut+\frac{1}{2}at^2\\\Rightarrow u=\frac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\frac{450-\frac{1}{2}\times 32.2\times 2^2}{2}\\\Rightarrow u=192.8\ ft/s$

$v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{192.8^2-0^2}{2\times 32.2}\\\Rightarrow s=577.20\ m$

The height the tomato would fall is 450+577.2 = 1027.2 m

6 0

4 years ago

What kind of simple machine is a catapult?

jok3333 [9.3K]

A LEVER is one type of simple machine.

7 0

4 years ago