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ludmilkaskok [199]
3 years ago
9

Before leaving an incident assignment, you should do all of the following EXCEPT FOR:

Physics
1 answer:
Free_Kalibri [48]3 years ago
7 0
<span>Self-dispatch to another incident</span>
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An airplane starts at rest and accelerates at 6.8 m/s2 at an angle of 39° south of west. After 9 s, how far in the westerly dire
cestrela7 [59]

Answer:36.8

Explanation:

7 0
3 years ago
Julian and Joshua each maintain a constant speed as they run laps around a 400-meter track. In the time it takes Julian to compl
Marysya12 [62]

Answer:

the time Joshua travels 1 mile is 12.5 min

Explanation:

Let's start by finding the distance traveled on each lap,

Let's reduce everything to the SI system

    R = 400 m

    d = 1 mile (1609 m / 1 mile) = 1609 m

    L = 2 pi R

    L = 2 pi 400

    L = 2513 m

Let us form a rule of proportions if 2 turns of Julian is 3 turns Joshua, for 1 turn of Joshua how many turns Julian took

    lap Julian = 2/3 turn Joshua

Let's calculate what distance is the same for both of them since they are on the same track

    1 lap = 2513 m

    d. Julian = 2/3 2513 m

    d Julian = 1675 m distance Joshua

Let us form the last rule of three or proportions if 1609 m you travel in 12 min how long it takes to travel 1675 m

    t Julian = 1675/1609 12

    t = 12.5 s

Since this is the distance Joshua travels, this is the time Joshua travels 1 mile

5 0
3 years ago
Read 2 more answers
A bicyclist starting at rest produces a constant angular acceleration of 1.30 rad/s2 for wheels that are 35.5 cm in radius.
Debora [2.8K]

Answer:

a) 0.462 m/s^2

b) 31.5 rad/s

c) 381 rad

d) 135m

Explanation:

the linear acceleration is given by:

a=\alpha *r\\a=1.30rad/s^2*(35.5*10^{-2}m)\\a=0.462m/s^2

the angular speed is given by:

\omega=\frac{v}{r}\\\\\omega=\frac{11.2m/s}{35.5*10^{-2}m}\\\\\omega=31.5rad/s

to calculate how many radians have the wheel turned we need the apply the following formula:

\theta=\frac{1}{2}\alpha*t^2\\\\t=\frac{\omega}{\alpha}\\\\t=\frac{31.5rad/s}{1.30rad/s^2}\\\\t=24.2s\\\\\theta=\frac{1}{2}*1.30rad/s^2*(24.2s)^2\\\\\theta=381rad

the distance is given by:

d=\theta*r

d=381rad*(35.5*10^{-2}m)\\d=135m

4 0
3 years ago
Your body is receiving backround radiation all the tim. Explain
adoni [48]
The uniform microwave radiation remaining from the Big Bang.


So, your body is always having background radiation and that means space!

3 0
3 years ago
A 60 N force is applied over a distance of 15 m. How much work was done?
GuDViN [60]

Answer:

900J

Explanation:

w =f×s

60×15

=900J

thus the k.e of the body is 900j

3 0
3 years ago
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