1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NISA [10]
3 years ago
7

Two objects have masses m and 5m, respectively. They both are placed side by side on a frictionless inclined plane and allowed t

o slide down from rest. Two objects have masses m and 5m, respectively. They both are placed side by side on a frictionless inclined plane and allowed to slide down from rest. A.The two objects reach the bottom of the incline at the same time.B.It takes the lighter object 5 times longer to reach the bottom of the incline than the heavier object. C.It takes the heavier object 10 times longer to reach the bottom of the incline than the lighter object. D.It takes the heavier object 5 times longer to reach the bottom of the incline than the lighter object. E.It takes the lighter object 10 times longer to reach the bottom of the incline than the heavier object.
Physics
1 answer:
Mama L [17]3 years ago
6 0

Answer:

A.The two objects reach the bottom of the incline at the same time.

Explanation:

-Since there is the incline is frictionless, there's no external force acting on the two objects except gravitational force(9.8N/kg).

-Gravitational acceleration ,9.8m/s^2, is equal for any two masses left in free fall despite the difference in massess.

-Therefore, the two bodies will reach the bottom of the incline at the exact same time.

You might be interested in
An archer fires an arrow at a castle 230 m away. The arrow is in flight for 6 seconds, then hits the wall of the castle and stic
Vika [28.1K]

Answer:

(a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

Explanation:

Given that,

Horizontal distance = 230 m

Time t = 6 sec

Vertical distance = 16 m

We need to calculate the horizontal component

Using formula of horizontal component

R =u\cos\theta t

Put the value into the formula

\dfrac{230}{6} = u\cos\theta

u\cos\theta=38.33.....(I)

We need to calculate the height

Using vertical component

H=u\sin\theta t-\dfrac{1}{2}gt^2

Put the value in the equation

16 =u\sin\theta\times6-\dfrac{1}{2}\times9.8\times6^2

u\sin\theta=\dfrac{16+9.8\times18}{6}

u\sin\theta=32.06.....(II)

Dividing equation (II) and (I)

\dfrac{u\sin\theta}{u\cos\theta}=\dfrac{32.06}{38.33}

\tan\theta=0.8364

\theta=\tan^{-1}0.8364

\theta=39.90^{\circ}

(a). We need to calculate the initial speed

Using equation (I)

u\cos\theta\times t=38.33

Put the value into the formula

u =\dfrac{230}{6\times\cos39.90}

u=49.96\ m/s

(b). We have already calculate the angle.

Hence, (a). The initial speed of the arrow is 49.96 m/s.

(b). The angle is 39.90°.

5 0
3 years ago
An object is dropped on Earth from a height of 15 m. What is the magnitude of the velocity of the object just as it hits the gro
ivolga24 [154]
Here, we know, according to 3rd Equation of Kinematics, 
v² - u² = 2as

Here, u = 0  [ Free fall ]
a = 9.8 m/s² [ constant value for the Earth system ]
s = 15 m

Substitute their values, 
v² - 0² = 2 * 9.8 * 15
v² = 294
v = √294
v = 17.15 m/s

In short, Your Answer would be Option D

Hope this helps!
8 0
3 years ago
Read 2 more answers
A father is pulling his child on a sled in the snow. According to Newton’s Third Law, the force the father exerts on the sled is
viktelen [127]
That is because there are other forces like the friction forces that apply differently on both of them. The frictional forces applied to the sled are smaller than they are on the father, for example, so it's possible for him to pull it.
5 0
3 years ago
43 kg bear slides, from rest, 15 m down a lodgepole pine tree, moving with a speed of 5.5 m/s just before hitting the ground. (a
olga2289 [7]

Answer:

-6327.45 Joules

650.375 Joules

378.47166 N

Explanation:

h = Height the bear slides from = 15 m

m = Mass of bear = 43 kg

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of bear = 5.5 m/s

f = Frictional force

Potential energy is given by

P=mgh\\\Rightarrow P=43\times -9.81\times 15\\\Rightarrow P=-6327.45\ J

Change that occurs in the gravitational potential energy of the bear-Earth system during the slide is -6327.45 Joules

Kinetic energy is given by

K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times 43\times 5.5^2\\\Rightarrow K=650.375\ J

Kinetic energy of the bear just before hitting the ground is 650.375 Joules

Change in total energy is given by

\Delta E=fh=-(\Delta K+\Delta P)\\\Rightarrow fh=-(650.375-6327.45)\\\Rightarrow fh=5677.075\\\Rightarrow f=\frac{5677.075}{h}\\\Rightarrow f=\frac{5677.075}{15}\\\Rightarrow f=378.47166\ N

The frictional force that acts on the sliding bear is 378.47166 N

5 0
2 years ago
Read 2 more answers
Hans observed properties of four different waves and recorded observations about each one in his chart.
bogdanovich [222]
The answer to your question is (Wave W is being diffracted, Wave X is being reflected, and waves Y and Z are being refracted.)


HOPE THIS HELPS YOU CAUSE IM DOING TEST AND I HOPE IM RIGHT AS WELL

PLZ GIVE ME THE BRAINLIEST ANSWER HAVE A GOOD DAY




8 0
2 years ago
Read 2 more answers
Other questions:
  • What is power? Question options: Power is the ability to do work. Power is the rate at which work is done. Power is the amount o
    14·2 answers
  • Describe what “melting point” means
    9·1 answer
  • An object accelerates at 20 m/s2. By how much does the speed change in one
    8·1 answer
  • What document details the type of medical care that you wish to receive if you become incapacitated due to a physical or mental
    10·2 answers
  • When developing an experimental design, which action could a scientist take to improve the quality of the results?
    14·1 answer
  • What is the definition of recoil velocity?
    8·2 answers
  • Which of the following are equivalent units?
    10·2 answers
  • Which one of the following statements is not true of free falling object
    9·1 answer
  • A point charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram
    14·1 answer
  • A wolf spider runs 75 cm west, then turns and runs 50 cm south. Which choice gives the correct solution for the resultant? Quest
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!