Given :
Mass =5kg
T
1
=20
∘
C,T
2
=100
∘
C
ΔT=100−20=80
∘
C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
From Gauss law we have
E = 2kx/r where x=linear charge density, r=distance from the wire=1.7 m
k =9 x 10^9 SI units.....we have been given E = 3.8 x 10^4 N/C ..... so plugging numbers we get
x = 3.59 x 10^ -6 C/ M (coulomb per meter) =linear charge density
Answer:

Explanation:
As we know that work done by electric force is given as

so here we know that charge is moving from

to another position
so we will have




What assignment, you have to work with me here i don't know what were working on