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Rufina [12.5K]
3 years ago
7

The Hubble Space Telescope is in a "Low-Earth Orbit" with an orbital period of 95min. Calculate the altitude of the HST's orbit

above the earth's surface. Express your answer either in meters.
Earth's radius: 6.371x106 m

Earth's mass: 5.97x1024kg

Note: you may either express your answer long-form (like 23145693870274), or you may enter it in scientific notation as #.##e+## (for example, 2.31x1013 would become 2.31e+13)

Note: This will require some algebraic manipulation.
Physics
1 answer:
laila [671]3 years ago
8 0

Answer:I don’t know please tell me

Explanation:

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Objects are lighter on the moon than they are on earth. if an object A weighs 25lbs on the Moon and another object B weighs 25 N
solong [7]

Answer:

a. Object A

Explanation:

The mass of an object implies the quantity of matter in it, while the weight is the amount of gravitational force applied on an object.

The object A has a mass of 25 lbs, but object B on the earth has a weight, W, of 25 N.

So that,

For object A on the moon, mass = 25 lbs

For object B on the earth, W = 25 N,

W = m x g

25 = m x 10                (g = 10 m/s^{2})

m = \frac{25}{10}

   = 2.5 lbs

Mass of object B is 2.5 lbs.

Therefore, the mass of the object A is more than that of B.

5 0
3 years ago
A machine is rolling a metal cylinder under pressure. The radius of the cylinder is decreasing at a constant rate of 0.05 inches
Luden [163]
Yes, the volume of the cylinder will remain constant. As the radius decreases, the height will increase to make sure that the volume is kept the same.
We have been given a value of dr/dt and are required to find dh/dt
Because the volume is constant, we can plug it into the formula for the volume of the cylinder and rearrange it to make h the subject:
128 = πr²h
h = 128/πr²
Now we differentiate both sides:
dh/dr = -256/πr³
Applying the chain rule:
dh/dt = dh/dr x dr/dt
dh/dt = (-256/πr³) x -0.05
dh/dt = 64/5πr³; substituting the value of r
dh/dt = 64/5π(1.5)³
dh/dt = 1.21 in/sec
4 0
4 years ago
What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unch
Alenkinab [10]

Answer:

Potential difference and charge will also increase.

Explanation:

Asking that :

What will happen to the charge and potential difference if the plate area were increased while the plate separation remains unchanged?

The charge is directly proportional to area of the plate. That is, increase in area of the plate of a capacitor will lead to the increase in the charges between the plates.

And since charge is also proportional to the magnitude of potential difference between the plates from the definition of capacitance of a capacitor which says that:

Q = CV

Therefore, increase in the area of the plate will also lead to increase in potential difference between the plates.

Therefore, if the plate area were increased while the plate separation remains unchanged, the charge and potential difference between them will also increase.

5 0
3 years ago
You are skateboarding in your friend's driveway. You hit a rock and your
nekit [7.7K]

Answer:

the rock hit the board you go flying because you board stops but you have energy still going so there for you go flying

Explanation:

3 0
3 years ago
Sam is moving house and is carrying a 300N box of books up a flight of steps 5m high, it takes her 30 seconds. Gary follows her
hjlf

Answer:

Sam is providing the biggest power i.e. 50 W

Explanation:

Sam is moving house and is carrying a 300N box of books up a flight of steps 5m high, it takes her 30 seconds.

Sam's power :

P_1=\dfrac{W_1}{t_1}\\\\P_1=\dfrac{F_1d}{t_1}\\\\P_1=\dfrac{300\times 5}{30}\\\\P_1=50\ W

Gary follows her carrying a bag of clothes doing 1000 J of work; it only takes him 25 seconds.

Gary's power :

P_2=\dfrac{W_2}{t_2}\\\\P_2=\dfrac{1000}{25}\\\\P_2=40\ W

So, it is clear that Sam is providing the biggest power.

4 0
3 years ago
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