It would be the last one. because adding fertilizers to the soil, makes the soil rich for a plant to grow "healthy"
Answer:
Yes, since the choice of the zero o potential energy is arbitrary.
Explanation:
The kinetic energy is due to the motion of the object. The expression for the kinetic energy is as follows;

Here, m is the mass of the object and v is the velocity of the object.
The kinetic energy can not be negative as the velocity is squared. It can be zero and positive.
Potential energy: It is the energy is due to the position of the object.
The expression for the potential energy is as follows;
PE= mgh
Here, g is the acceleration due to gravity and height.
Height can be taken from the reference point, zero which can be taken below zero and above zero. Zero is taken as origin. Below zero, the height is taken as negative and above zero, the height is taken as positive.
The potential energy can be zero, positive and negative.
The total energy is the sum of kinetic energy and potential energy.
E= KE + PE
Here, KE is the kinetic energy and PE is the potential energy.
Therefore, the option (B) is correct.
This problem must be solved using a sketch. I attached an illustration of the problem.
You must trace the ray that reflects from the top off the table to your eyes. This how eyesight works, light rays reflects off the objects into your eyes.
Law of reflection tells us that light ray reflects off the surface at the same angle in which it falls on it( i attached another illustration of this).
Now we can write tangens equations:

We solve for h:
Answer: Force F will be one-sixteenth of the new force when the charges are doubled and distance halved
Explanation:
Let the charges be q1 and q2 and the distance between the charges be 'd'
Mathematical representation of coulombs law will be;
F1=kq1q2/d²...(1)
Where k is the electrostatic constant.
If q1 and q2 is doubled and the distance halved, we will have;
F2 = k(2q1)(2q2)/(d/2)²
F2 = 4kq1q2/(d²/4)
F2 = 16kq1q2/d²...(2)
Dividing equation 1 by 2
F1/F2 = kq1q2/d² ÷ 16kq1q2/d²
F1/F2 = kq1q2/d² × d²/16kq1q2
F1/F2 = 1/16
F1 = 1/16F2
This shows that the force F will be one-sixteenth of the new force when the charges are doubled and distance halved