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3 years ago

How to calculate force without acceleration?

2 answers:

8 0

First of all, your question makes no sense. There wouldn't be any force if acceleration is zero.

Secondly, if you want to solve question in which acceleration is not given, you can use following formulas:
1.) F = dp/dt(dp = change in momentum, dt = change in time). In other words, rate of change of momentum gives you acceleration.
2.) Pressure = Force/Area
3.) Gravitational force = Gm1m2/r^2 ( G = universal gravitational constant, m1,m2 = masses, r = distance between their center.
4.) Magnetic force = q(vxB) [ q = charge, v = velocity of the particle, B= magnetic field].
5.) Electric force = qE [ E = electric field, q = charge]
6.) Force = surface tension x length.

These are the most important one's there are many methods by the way.

Hope this helps you and have a nice day/night ahead!

Oksanka [162]3 years ago

6 0

There are many ways to calculate force. However, they are completely different aspects. The force on an area is pressure, so F = p*A. In magnetic fields you use another formule (forgot the formule atm). Unless you define what kind of force you are looking for, I can't help you any further.

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If a flea can jump straight up to a height of 21.1 cm , what is its initial speed as it leaves the ground, neglecting air resist

Vikentia [17]

The flea jumps at high velocity, reaches zero velocity at the maximum height 21.1 cm before starting to fall. Solve for initial velocity given final velocity is zero.
since time is not given, use the equation:
v^2 = u^2 + 2as
convert gravity or displacement to have same units. 9.8 m/s = 980 cm/s
0 = u^2 + 2(-980)(21.1)
41356 = u^2
sqrt(41356) = u
203.4 cm/s = u

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4 years ago

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An object in circular motion moves along____________path

stellarik [79]

Answer:

Circular path

Explanation:

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3 0

3 years ago

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How many photons will be required to raise the temperature of 1.8 g of water by 2.5 k ?'?

tatyana61 [14]

Missing part in the text of the problem:
"<span>Water is exposed to infrared radiation of wavelength 3.0×10^−6 m"</span>

First we can calculate the amount of energy needed to raise the temperature of the water, which is given by
$Q=m C_s \Delta T$
where
m=1.8 g is the mass of the water
$C_s = 4.18 J/(g K)$ is the specific heat capacity of the water
$\Delta T=2.5 K$ is the increase in temperature.

Substituting the data, we find
$Q=(1.8 g)(4.18 J/(gK))(2.5 K)=18.8 J=E$

We know that each photon carries an energy of
$E_1 = hf$
where h is the Planck constant and f the frequency of the photon. Using the wavelength, we can find the photon frequency:
$\lambda = \frac{c}{f}= \frac{3 \cdot 10^8 m/s}{3 \cdot 10^{-6} m}=1 \cdot 10^{14}Hz$

So, the energy of a single photon of this frequency is
$E_1 = hf =(6.6 \cdot 10^{-34} J)(1 \cdot 10^{14} Hz)=6.6 \cdot 10^{-20} J$

and the number of photons needed is the total energy needed divided by the energy of a single photon:
$N= \frac{E}{E_1}= \frac{18.8 J}{6.6 \cdot 10^{-20} J} =2.84 \cdot 10^{20} photons$

4 0

3 years ago

Which of the following statements must be true if the net force on an object is zero? Choose all that apply.

Black_prince [1.1K]

Answer:

a) The object must have constant velocity.

d) The object must have zero acceleration.

Explanation:

We can solve the problem by using Newton's second law, which states that the net force acting on an object is equal to the product between mass and acceleration:

$F = ma$

where

F is the net force

m is the mass of the object

a is the acceleration

In this problem, the net force on the object is zero:

F = 0

This means that the acceleration of the object is also zero, according to the previous equation:

a = 0

So statement (d) is correct. Moreover, acceleration is defined as the rate of change of velocity:

$a=\frac{\Delta v}{\Delta t}$

Which means that $\Delta v=0$ , so the velocity is constant. Therefore, statement (a) is also correct. The other two statements are false because:

b)The object must be at rest. --> false, the object can be moving at constant velocity, different from zero

c)The object must be at the origin. --> false, since the object can be in motion

5 0

3 years ago

a bungee jumper momentarily comes to rest at the bottom of the dive before he springs back upward. at that moment, is the bungee

barxatty [35]

Answer:

Explanation:

No, the bungee jumper is not at equilibrium.

This can be explained when we consider a bungee jumper as a mass that is undergoing simple harmonic motion. At extreme points i.e. at the bottom, the velocity of the jumper is zero but not the acceleration because it is acting in the opposite direction that is why the jumper moves upward.

3 0

4 years ago

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