Answer:
Probability = 0.119
Step-by-step explanation:
P (Coronavirus) = P(Person online & corona) or P(Person offline & corona)
(0.70 x 0.02) + (0.30 x 0.35)
0.014 + 0.105
0.119
Answer:
A?
Step-by-step explanation:
I think it is A but I'm not 100% sure
Answer:
Step-by-step explanation:
Perform the multiplication and addition:
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<em>Comment on the squaring</em>
There are several ways you can find the square (x+4)².
- Use your knowledge that (x+a)² = x²+2ax+a².
- Use FOIL* to compute (x+4)(x+4) = x² +4x +4x +4² = x²+8x+16
- Use the distributive property: (x+4)(x+4) = x(x+4) +4(x+4) = x² +4x +4x +4² (same as FOIL for two binomials)
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* FOIL is mnemonic for {First, Outer, Inner, Last} referring to pairs of terms in the factors (x +a)(x +b). The x terms are the First terms. The Outer terms are the first x and b. The Inner terms are "a" and the second x. The Last terms are "a" and "b". You are to form the sum of those pairs of terms to find the product of the binomials.
Answer:
-4
Step-by-step explanation:
3+1 = 4 so just put a dash at the start and you ger -4
Answer:
f(x) = 26500 * (0.925)^x
It will take 7 years
Step-by-step explanation:
A car with an initial cost of $26,500 depreciates at a rate of 7.5% per year. Write the function that models this situation. Then use your formula to determine when the value of the car will be $15,000 to the nearest year.
To find the formula we will use this formula: f(x) = a * b^x. A is our initial value which in this case is $26500. B is how much the value is increasing or decreasing. In this case it is decreasing by 7.5% per year. Since the car value is decreasing we will subtract 0.075 from 1. This will result in the formula being f(x) = 26500 * (0.925)^x. Now to find the value of the car to the nearest year of when the car will be 15000 we plug 15000 into f(x). 15000 = 26500 * (0.925)^x. First we divide both side by 26500 which will make the equation: 0.56603773584=(0.925)^x. Then we will root 0.56603773584 by 0.925. This will result in x being 7.29968 which is approximately 7 years.
