Ask question

Ask question

All categories

3 years ago

15

If a boulder has a weight of 675,000 N what is it’s mass

1 answer:

Anarel [89]3 years ago

6 0

Weight = (mass) x (acceleration of gravity where the object is)

You didn't tell us WHERE the boulder is, so I have to assume that it's on Mars, where the acceleration of gravity is 3.71 m/s².

675,000 N = (mass) (3.71 m/s²)

Mass = (675,000 N) / (3.71 m/s²)

<em>Mass = 181,941 kilograms</em>

The same weight on Earth would suggest a mass of only 68,807 kg, so you can see how important it is to know where you are when you make your measurements.

You might be interested in

A train travels at a speed of 30 m/s. The train starts at an initial position of 1000 meters and travels for 30 seconds. What is

pychu [463]

1000 + 30x30 = 1900. Hope that helps

6 0

3 years ago

mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan

Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, $v_e$ , for the planet is $v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }$

Where;

$v_e$ = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, $M_E$

r = The radius of the planet = 3 × The radius of Earth, $R_E$

The escape velocity for Earth, $v_e_E$ , is therefore given as follows;

$v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }$

$\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } = \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E$

$v_e$ = 16 × $v_e_E$

Given that the escape velocity for Earth, $v_e_E$ ≈ 11,186 m/s, we have;

The escape velocity on the planet = $v_e$ ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0

3 years ago

A constant force of 5.00 N acts on a 2.50 kg object for 10.0 s. What are the changes in the object’s momentum and velocity?

dimulka [17.4K]

Hope this answer helps, cause Idk, I might be wrong, but I still, I used the correct formulas, so I might be correct

7 0

3 years ago

15. Calculate The coefficient of kinetic friction be-

allochka39001 [22]

Answer:

Wt = 26.84 [N]

Explanation:

In order to solve this problem we must use the definition of work in physics. Which tells us that this is equal to the product of force by distance.

In this case, we must sum the works of the force applied by the box and the friction force that also acts on the box.

The friction force is defined as the product of the normal force by the coefficient of friction.

f = N*μ

where:

N = normal force = m*g [N] (units of Newtons)

m = mass = 72 [kg]

g = gravity acceleration = 9.81 [m/s²]

f = friction force [N]

μ = friction coefficient = 0.21

f = 72*9.81*0.21

f = 148.32 [N]

Now the total work:

Wt = WF - Wf

where:

Wt = total work [J] (units of Joules)

WF = work by the pushing force [J]

Wf = work done by the friction force [J]

Wt = (160*2.3) - (148.32*2.3)

Wt = 26.84 [N]

Note: The friction force exerts a negative work, because this force is acting in opposite direction to the movement, therefore the negative sign.

3 0

3 years ago

The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.939 W/m2. The wave is incident u

Hatshy [7]

Answer:

The total energy is $T = 169.02 \ J$

Explanation:

From the question we are told that

The Poynting vector (energy flux ) is $k = 0.939 \ W/m^2$

The length of the rectangle is $l = 1.5 \ m$

The width of the rectangle is $w = 2.0 \ m$

The time taken is $t = 1 \ minute = 60 \ s$

The total electromagnetic energy falls on the area is mathematically represented as

$T = k * A * t$

Where A is the area of the rectangle which is mathematically represented as

$A= l * w$

substituting values

$A= 2 * 1.5$

$A= 3 \ m^2$

substituting values

$T = 0.939 * 3 * 60$

$T = 169.02 \ J$

5 0

4 years ago