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2 years ago

1. Apply a constant force of 50 N directed to the right of the 50 kg Box. (2 pts)

Physics

1 answer:

kotegsom [21]2 years ago

7 0

As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.

Then friction force = 80 Newtons but in the opposite direction.

Friction force = Mu * Normal force exerted by ground = Mu * weight of box

So we find Mu.

Mu = coefficient of friction between box and horizontal surface

= Force of friction / weight = 80 / 50 * 9.81 = 0.163

When an identical box is placed on top, the force of friction is

= Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons

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A flywheel in a motor is spinning at 590 rpm when a power failure suddenly occurs. The flywheel has mass 40.0 kg and diameter 75

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Answer:

Explanation:

Hello,

Let's get the data for this question before proceeding to solve the problems.

Mass of flywheel = 40kg

Speed of flywheel = 590rpm

Diameter = 75cm , radius = diameter/ 2 = 75 / 2 = 37.5cm.

Time = 30s = 0.5 min

During the power off, the flywheel made 230 complete revolutions.

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∇θ/t = (530 + ω₂) / 2

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460 = 295 + 0.5ω₂

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ω₂ = ω₁ + αt

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α = (ω₂ - ω₁) / t

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α = -260 / 0.5

α = -520rev/min

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0 = 590 +(-520)t

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t = 590 / 520

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X seconds = 1.13min

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Answer:

Explanation:

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