1. What is the total distance traveled? A 3.0m B 4.0m C 5.0m D 6.0m

__________ force is a fictitious force that some people believe causes you to feel as if you are being pushed outward from the c

jok3333 [9.3K]

The complete sentence is:
Centrifugal force is a fictitious force that some people believe causes you to feel as if you are being pushed outward from the center of a circle while traveling in uniform circular motion.

In fact, centrifugal force is an inertial force: it is not a real force, but it is due to the fact that the reference frame is rotating. The real force in a uniform circular motion is the centripetal force, which pushes towards the centre of the circle, and keeps the object in circular motion.

5 0

3 years ago

Read 2 more answers

How does water affect the coastal climate?

JulijaS [17]

Large bodies of water such as oceans, seas, and large lakes affect the climate of an area. Water heats and cools more slowly than land. Thus, in the summer, the coastal regions will stay cooler and in winter warmer. A more moderate climate with a smaller temperature range is created.

7 0

3 years ago

In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b

fomenos

Question is missing. Found on google:

"Part A What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units.

Part B

What is the net force on the ball during the hit?

Express your answer to two significant figures and include the appropriate units."

Solution:

A) $6000 m/s^2$

The acceleration of the ball is given by

$a=\frac{v-u}{t}$

where

v = 12 m/s is the final velocity

u = 0 is the initial velocity (the ball is stationary)

t = 2.0 ms = 0.002 s is the time of contact

Substituting,

$a=\frac{12-0}{0.002}=6.0 \cdot 10^3 m/s^2$

B) $8.4\cdot 10^2 N$

The force on the ball can be found by using Newton's second law:

$F=ma$

where

m = 140 g = 0.14 kg is the mass of the ball

$a=6.0\cdot 10^3 m/s^2$ is the acceleration

Substituting,

$F=(0.14)(6.0\cdot 10^3)=8.4\cdot 10^2 N$

3 0

3 years ago

URGENT!!!!!!! PLEASE HELP WITH THIS PHYSICS PROBLEM

Levart [38]

Explanation:

Let

$x_1$ = distance traveled while accelerating

$x_2$ = distance traveled while decelerating

The distance traveled while accelerating is given by

$x_1 = v_0t + \frac{1}{2}at^2 = \frac{1}{2}at^2$

$\:\:\:\:\:= \frac{1}{2}(2.5\:\text{m/s}^2)(30\:\text{s})^2$

$\:\:\:\:\:= 1125\:\text{m}$

We need the velocity of the rocket after 30 seconds and we can calculate it as follows:

$v = at = (2.5\:\text{m/s}^2)(30\:\text{s}) = 75\:\text{m/s}$

This will be the initial velocity when start calculating for the distance it traveled while decelerating.

$v^2 = v_0^2 + 2ax_2$

$0 = (75\:\text{m/s})^2 + 2(-0.65\:\text{m/s}^2)x_2$

Solving for $x_2,$ we get

$x_2 = \dfrac{(75\:\text{m/s})^2}{2(0.65\:\text{m/s}^2)}$

$\:\:\:\:\:= 4327\:\text{m}$

Therefore, the total distance x is

$x = x_1 + x_2 = 1125\:\text{m} + 4327\:\text{m}$

$\:\:\:\:= 5452\:\text{m}$

3 0

2 years ago

In some plants, the pistils don’t Form until a few days after the stamens do.How might this keep a plant from self pollinating

KATRIN_1 [288]

For a flower to be pollinated, pollen from an anther (which is located at the top of the stamen) needs to reach a stigma (at the top of the pistle.) Some plants are genetically capable of pollinating themselves if their own pollen reaches their own stigma; some plants are not capable of self pollination under any circumstances.

For plants that can genetically self pollinate, but would prefer not to, they can avoid this by having their pistil and pollen/stamens mature at different times. If the stamens mature first, the pollen will be dispersed by animals or wind or whatever dispersal mechanism it relies on. Then by the time the pistil is ready to be pollinated, there is no pollen left in that flower to land on the stigma.

3 0

3 years ago