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Artyom0805 [142]

3 years ago

11

Two charged objects have a repulsive force of 0.050 N. If the charge of both of the objects is doubled, then what is the new for

ce?

1 answer:

grandymaker [24]3 years ago

7 0

Answer: 4 times grease

Explanation: Force F= C · q1·q2/r². C = Coulomb's constant.

If charges double you have 2q1 and 2q2.

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(c) The plates are moved farther apart with each plate maintaining the same net charge. In a coherent paragraph-length response,

katrin2010 [14]

Answer:

Energy is applied on the charge to do work.

Explanation:

Work is only be done when one charge moves against the electric field of anther charge that require huge amount of energy because both have same charge and the force of repulsion occurs between them. Work is defined as the product of force and displacement so from this equation we can conclude that work is done when a force is applied on an object and it moves in the direction in which force is applied. If the force or energy is removed from the charge which is present in the electric field of another charge so it moves away from that charge and the work is also be done..

5 0

3 years ago

A bus with a vertical wind shield moves horizontally

Katena32 [7]

Answer:

(3) 53°

Explanation:

We want to measure the angle that the rains form with the vertical wind shield, so we have to measure the angle relative to the vertical. This means that we can write the following equation

$tan \theta = \frac{v_x}{v_y}$

where

$v_y = 30 km/h$ is the speed of the rain, which travels vertically

$v_x = 40 km/h$ is the speed of the bus, which travels horizontally

Substituting, we find

$\theta=tan^{-1}(\frac{40}{30})=53^{\circ}$

8 0

3 years ago

A straight fin fabricated from 2024 Aluminum alloy (k=185 W/mK) has a base thickness of t=3 mm and a length of L=15 mm. Its base

faltersainse [42]

Answer:

Explanation:

Attach is the solution

6 0

4 years ago

A snow ball is thrown upward at a speed of 27 m/s. How high is the snow ball 3.5 seconds later? Also, how fast is it moving at t

JulijaS [17]

Answer:

Dy = 111.66 [m]

t = 3.5 [s]

Explanation:

To solve this problem we must use the equations of kinematics.

$v_{f} = v_{o} - (g*t)\\$

where:

Vf = final velocity [m/s]

Vo = initial velocity = 27 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time = 3.5 [s]

Note: The negative sign of the equation means that the gravity acceleration goes in opposite direction

Vf = 27 - (9,81*3,5)

Vf = - 7.33 [m/s] (this negative sign indicates that at this moment the snowball is going downwards)

To find how high the snowball was we must use the following equation:

$Dy=v_{o} *t+\frac{1}{2}*g*t$

Dy = (27*3.5) + (0.5*9.81*3.5)

Dy = 94.5 + (17.16)

Dy = 111.66 [m]

5 0

3 years ago

An object is 30.0 cm to the left of a convex lens with a focal length of +8.0 cm. Draw a ray diagram of the setup showing the lo

Ostrovityanka [42]

The distance should be 11 cm and the image will be inverted (and smaller)
I used the Lens Equation:
$\frac{1}{obj.}+ \frac{1}{im.} = \frac{1}{f}$
Where:
obj. is the distance of the object
im. is the distance of the image
f is the focal length

4 0

4 years ago