Ask question

Ask question

All categories

Artyom0805 [142]

3 years ago

11

Two charged objects have a repulsive force of 0.050 N. If the charge of both of the objects is doubled, then what is the new for

ce?

1 answer:

grandymaker [24]3 years ago

7 0

Answer: 4 times grease

Explanation: Force F= C · q1·q2/r². C = Coulomb's constant.

If charges double you have 2q1 and 2q2.

You might be interested in

An B flat is played on a french horn, whose frequency is 466Hz.

scoray [572]

Answer:

Period of one vibration = 0.00215 second (Approx.)

Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)

Explanation:

Given:

Frequency of wave = 466 Hz

Find:

Period of one vibration

Wavelength {Is speed of sound is 343 m/s]

Computation:

Period of one vibration = 1/F

Period of one vibration = 1 / 466

Period of one vibration = 0.00215 second (Approx.)

Wavelength = Velocity / Frequency

Wavelength {Is speed of sound is 343 m/s] = 343 / 466

Wavelength {Is speed of sound is 343 m/s] = 0.736 m (Approx.)

3 0

2 years ago

Read 2 more answers

If you know the distance an object has traveled in a certain amount of time you can determine

Nutka1998 [239]

With that information, you can determine the object's speed.
Just divide the distance covered by the time to cover the distance.

If you also know the direction the object moved, then you can
determine its velocity. If you don't, then you can't.

5 0

3 years ago

Read 2 more answers

A ball is launched vertically with an initial speed of y˙0= 50 m/s, and its acceleration is governed by y¨=-g-cDy˙2, where the a

stira [4]

Answer:

Explanation:

Given

acceleration is given by

$a=-g-c_Dv^2$

where $\ddot{y}=a$

$\dot{y}=v$

Also acceleration is given by

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ds=\frac{v}{a}dv$

$\int ds=\int \frac{v}{-g-0.001v^2}dv$

$\Rightarrow Let -g-0.001v^2=t$

$-0.001\times 2vdv=dt$

$vdv=-\frac{dt}{0.002}$

$at\ v_0=50\ m/s,\ t=-g-0.001(50)^2$

$t=-g-2.5$

at $v=0,\ t=-g$

$\int_{0}^{s}ds=\int_{-g}^{-g-2.5}\frac{-dt}{0.002t}$

$\int_{0}^{s}ds=\int^{-g}_{-g-2.5}\frac{dt}{0.002t}$

$s=\frac{1}{0.002}lnt|_{-g}^{-g-2.5}$

$s=\frac{1}{0.002}\ln (\frac{g+2.5}{g})$

$s=113.608\ m$

when air drag is neglected maximum height reached is

$h=\frac{v_0^2}{2g}$

$h=\frac{50^2}{2\times 9.8}$

$h=127.55\ m$

3 0

3 years ago

A piece of solid copper, at 10oC, is dropped into a graduated cylinder of 100°C water. Which statement BEST describes the change

enot [183]

Answer:

D

Explanation:

just took the test

6 0

3 years ago

Read 2 more answers

Explain what voltage,current, resistance are and how they relate to Ohms law. Then give examples

SOVA2 [1]

Voltage is the difference in charge between two points.
Current is the rate the charge flows
Resistance is the tendency a material has to resist the flow of charge (current)
Combining voltage resistance and current Ohm developed the formula
V (Voltage)= I (Current) x R (Resistance)

3 0

3 years ago