I think the closest possible answer to this question is The air density increases and decreases repeatedly before returning to normal.Thank you for your question. Please don't hesitate to ask in Brainly your queries.
Answer:
-11.11 degree Celsius
Explanation:
The change was 44 degree fanhereit
To 56 degree fanhereit
Therefore the temperature range can be calculated as follows
56-44
= 12 degree fanhereit to Celsius
= 12-32×5/9
= -20×5/9
= 100/9
= -11.11 degree Celsius
Answer:
31.831 Hz.
Explanation:
<u>Given:</u>
The vertical displacement of a wave is given in generalized form as
![\rm y = A\sin(kx -\omega t).](https://tex.z-dn.net/?f=%5Crm%20y%20%3D%20A%5Csin%28kx%20-%5Comega%20t%29.)
<em>where</em>,
- A = amplitude of the displacement of the wave.
- k = wave number of the wave =
![\dfrac{2\pi }{\lambda}.](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Cpi%20%7D%7B%5Clambda%7D.)
= wavelength of the wave.- x = horizontal displacement of the wave.
= angular frequency of the wave =
.- f = frequency of the wave.
- t = time at which the displacement is calculated.
On comparing the generalized equation with the given equation of the displacement of the wave, we get,
![\rm A=0.02.\\k=30.\\\omega =200.\\](https://tex.z-dn.net/?f=%5Crm%20A%3D0.02.%5C%5Ck%3D30.%5C%5C%5Comega%20%3D200.%5C%5C)
therefore,
![\rm 2\pi f=200\\\\\Rightarrow f = \dfrac{200}{2\pi}=31.831\ Hz.](https://tex.z-dn.net/?f=%5Crm%202%5Cpi%20f%3D200%5C%5C%5C%5C%5CRightarrow%20f%20%3D%20%5Cdfrac%7B200%7D%7B2%5Cpi%7D%3D31.831%5C%20Hz.)
It is the required frequency of the wave.
Rotten fruit can be consumed by decomposers.
Answer:
![9.3\cdot 10^{37}](https://tex.z-dn.net/?f=9.3%5Ccdot%2010%5E%7B37%7D)
Explanation:
Power is defined as the energy produced (E) per unit of time (t):
![P= \frac{E}{t}](https://tex.z-dn.net/?f=P%3D%20%5Cfrac%7BE%7D%7Bt%7D)
This means that the energy produced in the Sun each second (1 s), given the power
, is
![E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J](https://tex.z-dn.net/?f=E%3DPt%3D%284.0%5Ccdot%2010%5E%7B26%7DW%29%281s%20%29%3D4.0%5Ccdot%2010%5E%7B26%7D%20J)
Each p-p chain reaction produces an amount of energy of
![E_1 = 4.3\cdot 10^{-12} J](https://tex.z-dn.net/?f=E_1%20%3D%204.3%5Ccdot%2010%5E%7B-12%7D%20J)
in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:
![n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BE%7D%7BE_1%7D%3D%5Cfrac%7B4.0%5Ccdot%2010%5E%7B26%7D%20J%7D%7B4.3%5Ccdot%2010%5E%7B-12%7D%20J%7D%3D9.3%5Ccdot%2010%5E%7B37%7D)