What is the change in weight of a hollow cylinder of height 8 cm and radius 3 cm when the air is pumped out of it
1 answer:
This question involves the concepts of density, weight, and volume.
The change in weight of the cylinder will be "2.72 x 10⁻³ N".
The change in weight of the cylinder will be equal to the weight of the air inside the cylinder which is being removed from it:
where,
= change in weight of cylinder = ?
= Weight of air inside cylinder =
= density of air = 1.225 kg/m³
- V = Volume of air inside the cylinder = πr²h = π(0.03 m)²(0.08 m) = 2.26 x 10⁻⁴ m³
- g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>ΔW = 2.72 x 10⁻³ N</u>
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4days and 12hours
Explanation:
Given parameters:
Average speed = 15m/s
Distance = 1800 miles
Unknown:
Number of days = ?
Solution:
Speed is the rate of change of distance with time;
Speed =
Since the unknown is number of days, it is a measure of time:
Time =
The distance from California to Lansing is 1800miles. The journey takes the truck drivers to and fro. It is a two way trip;
Total distance = 1800 miles x 2 = 3600miles
We need to convert miles to meters since that is the unit we can conveniently work with;
1 mile = 1609.34m
3600 miles = 3600 x 1609.34
= 5793638m
Inputting the values in the equation:
Time = = 386242.53s
Now we need to convert to day;
In a day, = 60 x 60 x 24 = 86,400s
1 day = 86400s
Therefore;
The number of days = = 4.47days
This implies that it will take them 4 days and approximately 12 hours.
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