What is the change in weight of a hollow cylinder of height 8 cm and radius 3 cm when the air is pumped out of it
1 answer:
This question involves the concepts of density, weight, and volume.
The change in weight of the cylinder will be "2.72 x 10⁻³ N".
The change in weight of the cylinder will be equal to the weight of the air inside the cylinder which is being removed from it:
where,
= change in weight of cylinder = ?
= Weight of air inside cylinder =
= density of air = 1.225 kg/m³
- V = Volume of air inside the cylinder = πr²h = π(0.03 m)²(0.08 m) = 2.26 x 10⁻⁴ m³
- g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>ΔW = 2.72 x 10⁻³ N</u>
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Answer:
The kinetic energy of the particle as it moves through point B is 7.9 J.
Explanation:
The kinetic energy of the particle is:
<u>Where</u>:
K: is the kinetic energy
: is the potential energy
q: is the particle's charge = 0.8 mC
ΔV: is the electric potential = 1.5 kV
Now, the kinetic energy of the particle as it moves through point B is:
Therefore, the kinetic energy of the particle as it moves through point B is 7.9 J.
I hope it helps you!