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sleet_krkn [62]
3 years ago
12

Selected properties of antimony (Sb) and iodine (I) are listed in the table below. Element Atomic radius (pm) First ionization e

nergy (kJ/mol) Electron affinity (kJ/mol) Electronegativity Sb 145 ? –103 2.05 I 140 1008 –295 ? Which predictions can most likely be made? Sb has a lower ionization energy but a higher electronegativity than I. Sb has a higher ionization energy but a lower electronegativity than I. Sb has a lower ionization energy and a lower electronegativity than I. Sb has a higher ionization energy and a higher electronegativity than I.
Chemistry
2 answers:
V125BC [204]3 years ago
7 0

Sb has a lower ionization energy and a lower electronegativity  than I.

Effectus [21]3 years ago
4 0

Let us check each statement one by one

a) Sb has a lower ionization energy but a higher electronegativity than I. : As per values given : Definitely Sb has lower ionization energy however the electronegativity of Sb is lower than that of iodine

b) Sb has a higher ionization energy but a lower electronegativity than I. FAlse:

Sb has lower ionization energy than I

c) Sb has a lower ionization energy and a lower electronegativity than I. True

d) Sb has a higher ionization energy and a higher electronegativity than I. False


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\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

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