All categories

3 years ago

A d orbital can hold ____ electrons. A. 2 B. 6 C. 10 D. 14

Chemistry

2 answers:

stiks02 [169]3 years ago

6 0

The answer is C. Ten electrons

borishaifa [10]3 years ago

4 0

Answer:

10 electrons

Explanation:

You might be interested in

Which of the following is an oxidation? Select all that apply

butalik [34]

Answer:

2Na=Ca(OH)000.1 AgBr=2KF 2KBr=LiNO

7 0

2 years ago

Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t

Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution = $3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}$

l = path length = 2.5 mm = 0.25 cm

$I_o$ = incident light

$I$ = transmitted light

$\epsilon$ = molar absorptivity coefficient = $855dm^3mol^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)$

$\log \frac{I_o}{I}=0.6947$

$\frac{I_o}{I}=10^{0.6947}=4.951$

If we consider $I_o$ = 100

then, $I=\frac{100}{4.951}=20.198$

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light $I_A$ = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

$\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100$

$\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%$

Therefore, the percentage reduction in intensity is 79.80 %

3 0

3 years ago

Is C2H6 empirical molecular or both

marshall27 [118]

Answer:

molecular

Explanation:

7 0

3 years ago

4NH3 + 3O2 --> 2N2 + 6H2O

larisa86 [58]

The balanced reaction is:

4NH3 + 3O2 --> 2N2 + 6H2O

We are given the amount of reactants to be used for the reaction. This will be the starting point of our calculation.

83.7g of O2 ( 1 mol / 32 g) = 2.62 mol O2

2.81 moles of NH3

From the balanced reaction, we have a 4:3 ratio of the reactants. The limiting reactant would be oxygen. We will use the amount for oxygen for further calculations.

2.62 mol O2 (6 mol H2O / 3 mol O2) (18.02 g H2O / 1 mol H2O) = 94.42 g H2O

8 0

3 years ago

To explain the photoelectric effect, Albert Einstein linked the photoelectric effect to an idea from which scientist?

Georgia [21]

Max planck
hope i helped!

7 0

2 years ago

Read 2 more answers