Answer:
option a.
radius of the circle=3 units.
area of the circle= pi×r²
area of circle=pi×3²
area of circle=pi×9units²
1/2 yards times ) is 3, so 1/2 would be the answer.
Answer:
x = 2
Step-by-step explanation:
The product of distances from the intersection of secants to the near and far intersections with the circle are the same. For a tangent, the near and far points of intersection with the circle are the same. This relation tells us ...
(2√3)(2√3) = x(x +4)
12 = x² +4x
16 = x² +4x +4 . . . . . add the square of half the x-coefficient to complete the square
4² = (x +2)² . . . . . . . . write as squares
4 = x +2 . . . . . . . . . . positive square root
2 = x . . . . . . . . . . . . . subtract 2
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<em>Alternate solution</em>
If you believe x to be an integer, you can look for factors of 12 that differ by 4.
12 = 1×12 = 2×6 = 3×4
The factors 2 and 6 differ by 4, so x=2 and x+4=6.
soln,
here area of base = 25/4 unit ^ 2
height of the prism = 8/5 unit
so,
volume of prism = area of base x height of the prism
so the volume of the prism is 10 unit^2
