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Marta_Voda [28]
3 years ago
7

Decide whether the relation defines a function.

Mathematics
2 answers:
levacccp [35]3 years ago
4 0
B. Not a function because both (3,6) (4,6) have the same y making them not a function
Sever21 [200]3 years ago
3 0

This is a function because each input (x-value) has only one output (y-value). If an input (x-value) has more than one output (y-value) it is not a function. It is still a function if an output has more than one input.

Your answer is A

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|-9| + |12| = ?
antoniya [11.8K]

Answer:

21

Step-by-step explanation:

-9=9

9+12=21

6 0
2 years ago
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Find the area of a square with sides 17 centimeters long.
pickupchik [31]

Answer:

289 cm²

Step-by-step explanation:

Length (L) = 17 cm

Area of a square

= L²

= (17cm)²

= 289 cm²

7 0
3 years ago
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Jackie scored 81 and 87 on her first two quizzes . Write and solve a compound inequality to find the possible values for a third
asambeis [7]

Answer:

The third score must be larger than or equal to 72, and smaller than or equal 87

Step-by-step explanation:

Let's name "x" the third quiz score for which we need to find the values to get the desired average.

Recalling that average grade for three quizzes is the addition of the values on each, divided by the number of quizzes (3), we have the following expression for the average:

average=\frac{81+87+x}{3}

SInce we want this average to be in between 80 and 85, we write the following double inequality using the symbols that include equal sign since we are requested the average to be between 80 and 85 inclusive:

80\leq average\leq 85\\80\leq \frac{81+87+x}{3} \leq 85\\80\leq \frac{168+x}{3} \leq 85

Now we can proceed to solve for the unknown "x" treating each inaquality at a time:

80\leq \frac{168+x}{3}\\3*80\leq 168+x\\240\leq 168+x\\240-168\leq x\\72\leq x

This inequality tells us that the score in the third quiz must be larger than or equal to 72.

Now we study the second inequality to find the other restriction on "x":

\frac{168+x}{3} \leq 85\\168+x\leq 85 *3\\168+x\leq 255\\x\leq 255-168\\x\leq 87

This ine72\leq x} \leq 87quality tells us that the score in the third test must be smaller than or equal to 87 to reach the goal.

Therefore to obtained the requested condition for the average, the third score must be larger than or equal to 72, and smaller than or equal 87:

4 0
3 years ago
Find the mean, meadian, mode and range for each set of data 6, 9, 2, 4, 3, 6, 5
Helga [31]

Mean: Add up the numbers and divide the sum by the number of values in the set.

6 + 9 + 2 + 4 + 3 + 6 + 5 = 35

35 / 7 = 5

Median: Sort the set from the smallest value to the largest value and select the number in the middle. If the count of the set if even, then select the two middle values and take their mean average.

2, 3, 4, 5, 6, 6, 9

            ^

So, the median average is 5.

Mode: What number appears the most frequently?

The mode of the set is 6 because it appears twice.

Range: Sort the set by ascending order and take the smallest value and subtract that from the largest value in the set.

9 - 2 = 7

The range is 7.

6 0
3 years ago
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The circumference of C is 72 cm. What is the length of (the minor arc)? A. 90 cm B. 10 cm C. 45 cm D. 8 cm E. 9 cm F. 7.2 cm
dangina [55]

Answer:

e. 9cm

Step-by-step explanation:

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3 years ago
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