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3 years ago

Decide whether the relation defines a function.

Mathematics

2 answers:

levacccp [35]3 years ago

4 0

B. Not a function because both (3,6) (4,6) have the same y making them not a function

Sever21 [200]3 years ago

3 0

This is a function because each input (x-value) has only one output (y-value). If an input (x-value) has more than one output (y-value) it is not a function. It is still a function if an output has more than one input.

Your answer is A

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Ahmad run 5 kilometres. If he completed 15% of the race. How many kilometres is the race?

stepladder [879]

Answer:

x = 33.33 kilometers

Step-by-step explanation:

you could make use of the percent, base, and rate formula here. we know that 15% is the rate, 5 kilometers is the percent, therefore what we are looking for is our base.

$\frac{percent}{base} =\frac{rate}{100}$

$\frac{5}{x}=\frac{15}{100}$ ; cross multiply.

15x = 500

x = 33.33 kilometers

therefore, the race is 33.33 kilometers.

4 0

3 years ago

Read 2 more answers

What’s the correct answer for this question?

Brut [27]

Answer:

Step-by-step explanation:

First finding height using Pythagoras theorem

(H)²=(B)²+(P)²

8.2²=5.4²+P²

P² = 67.24 - 29.16

P² = 38.08

P = 6.2

Now

Volume of cone = (1/3)πr²h

= (1/3)(3.14)(5.4)²(6.2)

= (1/3)(567.9)

= 189.2 cm³

6 0

2 years ago

Se tiene un rectángulo cuya base mide el doble que su altura y su área es 12

irina [24]

Answer:

Part 1) The perimeter is $P=6\sqrt{6}\ cm$

Part 2) The diagonal is $d=\sqrt{30}\ cm$

Step-by-step explanation:

The question in English is

You have a rectangle whose base is twice the height and its area is 12

square centimeters. Calculate the perimeter of the rectangle and its diagonal

step 1

Find the dimensions of rectangle

we know that

The area of rectangle is equal to

$A=bh$

$A=12\ cm^2$

$bh=12$ ----> equation A

The base is twice the height

$b=2h$ ----> equation B

substitute equation B in equation A

$(2h)h=12\\2h^2=12\\h^2=6\\h=\sqrt{6}\ cm$

Find the value of b

$b=2\sqrt{6}\ cm$

step 2

Find the perimeter of rectangle

The perimeter is given by

$P=2(b+h)$

substitute

$P=2(2\sqrt{6}+\sqrt{6})\\P=6\sqrt{6}\ cm$

step 3

Find the diagonal of rectangle

Applying the Pythagorean Theorem

$d^2=b^2+h^2$

substitute

$d^2=(2\sqrt{6})^2+(\sqrt{6})^2$

$d^2=30$

$d=\sqrt{30}\ cm$

3 0

3 years ago

Solve the inequality.2/5 ≥ w -3/5 A. w ≤1/2 B. w ≤ 1 C. w ≥ 1 D. w ≤1/5

Sunny_sXe [5.5K]

We must solve 2/5 ≥ w -3/5. Note that w is already +, so leave it where it now is. Add 3/5 to both sides of this inequality:

2/5 + 3/5 ≥ w - 3/5 + 3/5

Then: 1 ≥ w, or w ≤ 1 (answer)

6 0

3 years ago

There are two positive numbers. four times the small number plus 3 times the big number is 41. two times the small number plus t

xxTIMURxx [149]

The small number is 2 the large number is 11.
4(2)+11(3)=41
2(2)+11=15
11(10) -2(6) = 98

hope that helps

4 0

2 years ago