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Marta_Voda [28]
3 years ago
7

Decide whether the relation defines a function.

Mathematics
2 answers:
levacccp [35]3 years ago
4 0
B. Not a function because both (3,6) (4,6) have the same y making them not a function
Sever21 [200]3 years ago
3 0

This is a function because each input (x-value) has only one output (y-value). If an input (x-value) has more than one output (y-value) it is not a function. It is still a function if an output has more than one input.

Your answer is A

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3/4 x 3 2/5 - 5/5(find the value of each of the following) ​
Triss [41]

The value of the given expression is \frac{-13}{20}.

Solution:

Given expression is \frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}.

Let us first convert mixed fraction into improper fraction.

3\frac{2}{5}=\frac{(3\times5)+2}{5}=\frac{17}{5}

Substitute this in the given expression.

\frac{3}{4} \times3\frac{2}{5}-\frac{5}{5}=\frac{3}{4} \times\frac{7}{15}-\frac{5}{5}

                  =\frac{21}{60}-\frac{5}{5}

To simplify the above expression, 21 and 60 are cancelled by 3.

                 =\frac{7}{20}-\frac{1}{1}

Do cross multiplication to make the denominator same.

                 =\frac{7}{20}-\frac{20}{20}

                 =\frac{7-20}{20}

                 =\frac{-13}{20}

The value of the given expression is \frac{-13}{20}.

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3 years ago
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Answer:

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bixtya [17]
I got radius= 54
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