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Fofino [41]
3 years ago
8

If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint:

Note that the solution composition is stated in terms of CuSO4 and that the solid that crystallizes is the hydrate CuSO4⋅5H2O.]
Chemistry
1 answer:
Andrew [12]3 years ago
7 0

Answer:

Mass of CuSO4.H2O obtained: m_{total}=19.52 g

Explanation:

The molecular weight of the salt is: M=159.5 g/mol

<u>In the solution</u>: 12.5 g of CuSO4

In moles: n=\frac{12.5 g}{159.5 g/mol}=0.078 mol

<u>Mass of wate</u>r:

5 moles of water per mol of salt: m=\frac{5mol}{1mol}*0.078mol*\frac{18g}{mol}=7.02 g

Mass of CuSO4.H2O obtained: m_{total}=12.5 g + 7.02 g=19.52 g

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Answer:

5.6 seconds

Explanation:

The reaction follows a zero-order in dinitrogen monoxide

Rate = k[N20]^0 = change in concentration/time

[N20]^0 = 1

Time = change in concentration of N2O/k

Initial number of moles of N2O = 300 mmol = 300/1000 = 0.3 mol

Initial concentration = moles/volume = 0.3/4 = 0.075

Number of moles after t seconds = 150 mmol = 150/1000 = 0.15 mol

Concentration after t seconds = 0.15/4 = 0.0375 M

Change in concentration of N2O = 0.075 - 0.0375 = 0.0375 M

k = 0.0067 M/s

Time = 0.0375/0.0067 = 5.6 s

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Which mixture would be best to use as a wash for removal of the alkylcatechol from skin exposed to poison ivy?water and baking s
Rudiy27

The question is incomplete. Here is hte complete question.

The components of poison ivy and poison oak that produce the characteristic itchy rash are cathecols substituted with long-chain alkyl groups. The image is attached.

If you were exposed to poison ivy, which of the treatments below would you apply to the affected area? Justify your choice.

(a) Wash the area with cold water.

(b) Wash the area with dilute vinegar or lemon juice.

(c) Wash the area with sopa and water.

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Explanation: Alkyl is hydrophobic, which means it doesn't "mix" with water. To make it more soluble in water, soap helps to dissolve the chemical compound. As shown in the image, alkylcathecol is mildly alkaline. Baking soda is a salt that also helps dissolve it by ionizing with the -OH group, which makes it more soluble.

Although lemon juice and vinegar are acids, they are weak acids and so, won't have a strong effect on the alkylcathecol.

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