If the concentration of a saturated solution at 0∘C is 12.5 gCuSO4/100 g soln, what mass of CuSO4⋅5H2O would be obtained? [Hint:
1 answer:
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(1) Seven electrons
1s² 2s²2p³
There are two electrons in the 2s subshell and three in the 2p subshell. The remaining two electrons are in the inner 1s subshell.
(2) 22 electrons
1s² 2s²2p⁶ 3s²3p⁶ 4s²3d²
There are two electrons in the 4s subshell and two in the 2p subshell. The remaining 18 electrons are in the inner subshells.
(3) 17 electrons
1s² 2s²2p⁶ 3s²3p⁵
There are two electrons in the 3s subshell and five in the 2p subshell. The remaining 10 electrons are in the inner subshells.
(4) n = 4, l = 2
(5) N=2 I=0 MI=0
(6) There can be two electrons in one orbital maximum. The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max.
(7) n = 4 can hold up to 16 electrons
There are 4 sublevels; 42, 4p, 4d and 4f
4s (1 orbital), 4p (3 orbitals)
4d (5 orbitals), 4f (7 orbitals)
Maximum number of electrons in energy level: 16
s = 1 orbital
p = 3 orbitals
d = 5 orbitals
f = 7 orbitals
Add these up;
1 + 3 + 5 + 7 = 16
(8) 14 electrons If l = 3, the electrons are in an f subshell. The number of orbitals with a quantum number l is 2l + 1, so there are 2×3 + 1 = 7 f orbitals. Each orbital can hold two electrons, so the f subshell can hold 14 electrons.
sorry i didn't do the last two.. also sorry if some or none of these are correct, i tried my best
