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anyanavicka [17]
3 years ago
11

When uranium-235 atoms undergo fission, ________ is/are produced?

Chemistry
1 answer:
elena-s [515]3 years ago
8 0
Smaller atoms ; free neutrons and energy
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Is ineffective collision's the answer? Please correct me if not, thank you. :)
AleksAgata [21]
Yes! You're correct! Hope this helps! :D
6 0
3 years ago
We make a basic solution by mixing 50. mL of 0.10 M NaOH and 50. mL of 0.10 M Ca(OH)2. It requires 250 mL of an HCl solution to
andreyandreev [35.5K]

<u>Answer:</u> The correct answer is Option 5.

<u>Explanation:</u>

  • To calculate the molarity of the solution after mixing 2 solutions, we use the equation:

M=\frac{n_1M_1V_1+n_2M_2V_2}{V_1+V_2}

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of the NaOH.

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of the Ca(OH)_2

We are given:

n_1=1\\M_1=0.10M\\V_1=50mL\\n_2=2\\M_2=0.1\\V_2=50mL  

Putting all the values in above equation, we get:

M=\frac{(1\times 0.1\times 50)+(2\times 0.1\times 50)}{50+50}\\\\M=0.15M

  • To calculate the molarity of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base.

We are given:

n_1=1\\M_1=?M\\V_1=250mL\\n_2=1\\M_2=0.15M\\V_2=100mL

Putting values in above equation, we get:

1\times M_1\times 250=1\times 0.15\times 100\\\\M_1=0.06M

Hence, the correct answer is Option 5.

7 0
3 years ago
1.  You have 10 grams of HCl, how many moles of HCl do you have?  
Oxana [17]

Explanation:

36.5gm (Molar mass) = 1mole

1 gram = 1/36.5 mole

10grams =(1/36.5) x 10 moles

= 0.027 x 10 moles

=0.27moles

4 0
3 years ago
A substance that has a uniform composition and is able to be separated by physical means
azamat
The answer is homogeneous mixture. It is a mixture which has uniform composition and properties all throughout. Mixtures can be separated by physical processes. Mixtures are systems that consist of two or more substances which are mixed but not chemically combined.
7 0
3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 72.4 grams of AlCl3
svlad2 [7]

Answer:  131 g of bromine is required.

Explanation:

The balanced equation will be :

2AlCl_3+3Br_2\rightarrow 2AlBr_3+3Cl_2

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

moles of AlCl_3

\text{Number of moles}=\frac{72.4g}{133g/mol}=0.544moles

According to stoichiometry :

2 moles of AlCl_3 require  = 3 moles of Br_2

Thus 0.544 moles of AlCl_3 require=\frac{3}{2}\times 0.544=0.816moles  of Br_2

Mass of Br_2=moles\times {\text {Molar mass}}=0.816moles\times 160g/mol=131g

Thus 131 g of bromine is required.

5 0
3 years ago
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