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Mice21 [21]
3 years ago
7

What temperature change in °C is produced when 4430 Joules are absorbed by 237 grams of water?

Chemistry
1 answer:
lesantik [10]3 years ago
4 0

Answer:

4.46 °C

Explanation:

Step 1: Given and required data

  • Energy absorbed (Q): 4430 J
  • Mass of water (m): 237 g
  • Specific heat of water (c): 4.186 J/g.°C

Step 2: Calculate the temperature change

We will use the following expression.

Q = c × m × ΔT

ΔT = Q / c × m

ΔT = 4430 J / (4.186 J/g.°C) × 237 g

ΔT = 4.46 °C

The temperature change is 4.46 °C.

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N is newtons so it would be false
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Answer:

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5 0
3 years ago
What is the ph of a solution which is 0.025 m in weak base and 0.037 m in the conjugate weak acid (ka = 7.1 × 10–6)?
Elden [556K]
Hello!

This question can be solved using the Henderson-Hasselbach equation, but first we need to know the value of pKa

pKa= -log(Ka)= -log(7,1*10⁻⁶)=5,15

Now, we apply the equation:

pH=pKa+log  \frac{[A^{-}] }{[HA]} =5,15+log( \frac{0,025M}{0,037M} )=4,98

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Have a nice day!


4 0
4 years ago
Please help.<br> Which organic product is formed in the reaction shown in the diagram?
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The organic product formed in the reaction shown in the image would be bromoethane.

<h3>Substitution reaction in alkanes</h3>

Alkanes, such as ethane undergoes a substitution reaction with halogens such as bromine to produce haloethanes.

For example, the equation of the reaction between ethane and bromine water is as below:

C_2H_6 + Br_2 --- > C_2H_5Br + HBr

The products formed are bromoethane and hydrobromic acid.

More on substitution reactions in alkanes can be found here: brainly.com/question/16811879

#SPJ1

3 0
3 years ago
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