Question

Write Lewis structural formulas for the following molecules:

Answer 1

Answer :  The Lewis-dot structure of the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

(1) The given molecule is, $NH_3$

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $NH_3$ = 5 + 3(1)  = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(2) The given molecule is, $SO_2$

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $SO_2$ = 6 + 2(6)  = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(3) The given molecule is, $CH_3OH$

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $CH_3OH$ = 4 + 4(1) + 6  = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(4) The given molecule is, $HNO_2$

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $HNO_2$ = 1 + 5 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(5) The given molecule is, $N_2$

As we know that nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in $N_2$ = 2(5) = 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

(6) The given molecule is, $CH_2O$

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in $CH_2O$ = 4 + 2(1) + 6  = 12

According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.