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ella [17]
3 years ago
13

Write Lewis structural formulas for the following molecules:

Chemistry
1 answer:
lubasha [3.4K]3 years ago
8 0

Answer :  The Lewis-dot structure of the following molecules are shown below.

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

(1) The given molecule is, NH_3

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in NH_3 = 5 + 3(1)  = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

(2) The given molecule is, SO_2

As we know that sulfur and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in SO_2 = 6 + 2(6)  = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(3) The given molecule is, CH_3OH

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_3OH = 4 + 4(1) + 6  = 14

According to Lewis-dot structure, there are 10 number of bonding electrons and 4 number of non-bonding electrons.

(4) The given molecule is, HNO_2

As we know that hydrogen has '1' valence electron, nitrogen has '5' valence electrons and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in HNO_2 = 1 + 5 + 2(6) = 18

According to Lewis-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.

(5) The given molecule is, N_2

As we know that nitrogen has '5' valence electrons.

Therefore, the total number of valence electrons in N_2 = 2(5) = 10

According to Lewis-dot structure, there are 6 number of bonding electrons and 4 number of non-bonding electrons.

(6) The given molecule is, CH_2O

As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron and oxygen has '6' valence electrons.

Therefore, the total number of valence electrons in CH_2O = 4 + 2(1) + 6  = 12

According to Lewis-dot structure, there are 8 number of bonding electrons and 4 number of non-bonding electrons.

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Explanation:

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  • Since NaOH is in excess, so H₂SO₄  is the limiting reactant.
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n of H₂SO₄ = mass/molar mass = (355.0 g)/(98.0 g/mol) = 3.622 mol.

Using cross multiplication:

∵ 1.0 mol H₂SO₄ produces → 1.0 mol of Na₂SO₄.

∴ 3.622 mol H₂SO₄ produces → 3.662 mol of Na₂SO₄.

  • Now, we can get the theoretical mass of Na₂SO₄:

∴ mass of Na₂SO₄ =  no. of moles x molar mass = (3.662 mol)(142.04 g/mol) = 514.5 g.

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