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makvit [3.9K]
3 years ago
6

16, 33, 31, 33, 84, 11, 44, 82, 82, 84Mean:Mode:Median:Range:​

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0
Mean is 10

Because add them all up then divide by how many numbers there are
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Can someone help me with this? I'm really confused. Im supposed to be doing a projet, but i don't know how to do it
mr_godi [17]

Answer:

Step-by-step explanation:

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5 0
3 years ago
I have no idea!! Please help!!!
Ber [7]
The area of a traingle is \frac{1}{2}bh
So we need to know the base and the height
To work out the sides of a right angle triangle we can use a²+b²=c
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Because this triangle is isoceles we know that a and b are the same

a²+b²=c²
a²+a²=c²
2a²=c²
2a²=(x√6)²
2a²=(x√6)(x√6)
2a²=x²+x√6+x√6+6
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A=\frac{1}{2}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}×\sqrt{\frac{x^{2}+x\sqrt{6}+x\sqrt{6}+6}{2}}
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8 0
3 years ago
Convert 5/6 hour to minutes 1 hour = 60 mins.
masya89 [10]

Answer:

50 minutes.

Step-by-step explanation:

We solve this question by proportions, using rule of three.

One hour is 60 minutes.

5/6 hour

This is:

\frac{5}{6}*60 = \frac{5*60}{6} = 5*10 = 50

50 minutes.

3 0
3 years ago
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Karolina [17]

hope it helped. I have solved in the same paper. plz don't mind.

7 0
3 years ago
Watch day about 75,000 people visit Paris, France. Use commutative property to write two equivalent expressions that could be us
Studentka2010 [4]

Answer:

5\times 75,000 and 75,000\times 5

Step-by-step explanation:

We have been given that about 75,000 people visit Paris, France. We are asked to write two equivalent expressions that could be used to find the number of people that visits over a 5- day period .

To find the number of people over a 5-day period, we will multiply 75,000 people by 5 as:

\text{Number of people that visits over a 5-day period}=75,000\times 5

Commutative property of multiplication states that we can multiply numbers in any order.

Upon switching the order while multiplying, we will get:

\text{Number of people that visits over a 5-day period}=5\times 75,000

Therefore, our required equivalent expressions would be 5\times 75,000 and 75,000\times 5.

5 0
3 years ago
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