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icang [17]
3 years ago
14

Ine L has equation 2x - 3y = 5. Line M passes through the point (3, -10) and is parallel to line L. Determine the equation for l

ine M.
a.2x + 3y = -24
b.2x - 3y = 36
c.2x - 3y = -10
d.3x + 2y = -24
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
7 0

First of all, let's find the slope of line L. To find the slope of a line, you write it in the explitic form y = mx+q, and consider the coefficient m. So, we have

2x - 3y = 5 \iff 3y = 2x-5 \iff y = \dfrac{2}{3} x - \dfrac{5}{3}

So, the slope of line L is 2/3.

Two lines are parallel if they have the same slope. So, line M has slope 2/3 as well, and we know that it passes through the point (3, -10).

When you are given the slope m and a point (x_0,y_0) of a line, its equation is given by

y-y_0=m(x-x_0)

So, if you plug your values, you have

y+10 = \dfrac{2}{3}(x-3)

which you can simplify into

y+10 = \dfrac{2}{3}x-2

y = \dfrac{2}{3}x-12

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mamaluj [8]

Answer:

-  \frac{1}{3}

Step-by-step explanation:

The only thing important in this question in the original equation is the slope, which is 3, the multiplyer for x. To find the opposite slope follow the steps below.

The first step is to make the original slope into a fraction.

\frac{3}{1}

Then flip the numerator and denominator.

\frac{1}{3}

Now multiply this value by -1.

\frac{1}{3}  \times ( - 1) =  -  \frac{1}{3}

There is the opposite slope of 3.

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