All categories

2 years ago

How many total atoms in 5 mg(NO3)2

Chemistry

2 answers:

sergeinik [125]2 years ago

6 0

Answer:

5 Mg (magnesium), 2 N (nitrogen), and 6 O (oxygen) -- total of 13 atoms

Cerrena [4.2K]2 years ago

3 0

There are 45 as 1 mg(NO3)2 = 9 atoms.

You might be interested in

Can you let me know which of these are homogeneous solutions

Svetllana [295]

Cement is the answer

7 0

3 years ago

If a farmer wants to increase the health of his crops, he could apply a nitrogen-based fertilizer. why is nitrogen important to

Finger [1]

Not only for plants, but also for every organism and every life form nitrogen is important because it poses as catalyst that supports different is chemical reactions of growth. N is filled with chlorophyll that actually gives you the answer on the question as chlorophyll allow plant to perform photosynthesis by absorbing energy from light that leads to the growth. So, it is important because it provides photosynthesis.

8 0

2 years ago

How does carbon dioxide get into the atmosphere?

e-lub [12.9K]

Answer:

By condensation.

Explanation:

Have a nice day dear

3 0

2 years ago

Read 2 more answers

ICMP scanning involves in checking for the live systems, which can be done by sending the following ping scan request to a host.

abruzzese [7]

Answer:

ICMP Echo Request

Explanation:

ICMP Echo Request is a form of probe or message sent by a user to a destination system.

5 0

3 years ago

If you have 16 g of manganese (II) nitrate tetrahydrate, how much water is required to prepare 0.16 M solution from this amount

Schach [20]

Answer: The amount of water required to prepare given amount of salt is 398.4 mL

Explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = 0.16 M

Given mass of manganese (II) nitrate tetrahydrate = 16 g

Molar mass of manganese (II) nitrate tetrahydrate = 251 g/mol

Putting values in above equation, we get:

$0.16M=\frac{16\times 1000}{251\times \text{Volume of solution}}\\\\\text{Volume of solution}=\frac{16\times 1000}{251\times 0.16}=398.4mL$

Volume of water = Volume of solution = 398.4 mL

Hence, the amount of water required to prepare given amount of salt is 398.4 mL

4 0

3 years ago