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tigry1 [53]
3 years ago
9

If you want to form a kinetic enolate, you want to:______.A. use a strong, non-nucleophilic base such as LDA.B. use a protic sol

vent.C. use a low temperature.D. both use a strong, non-nucleophilic base such as LDA and use a low temperature.E. both use a strong, non-nucleophilic base such as LDA and use a protic solvent.F. both use a protic solvent and use a low temperature.
Chemistry
1 answer:
stellarik [79]3 years ago
3 0

Answer:

D. both use a strong, non-nucleophilic base such as LDA and use a low temperature.

Explanation:

The more stable enolate is the thermodynamic enolate, and a less stable is known as the kinetic enolate.

The less stable enolate has a less substituted product, while the more stable product has a more substituted product.

Now, to form a kinetic enolate, we need to choose a strong, non-nucleophilic base such as LDA to attract hydrogen from the less substituted site. However, an increase in temperature results in an increase in a reaction, which leads to the formation of a stable product.

So, to form the kinetic enolate, a low temperature will be required.

Thus, To form a kinetic enolate, both use a strong, non-nucleophilic base such as LDA and use a low temperature.

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A sample of nitrogen gas collected at a pressure of 1.03 atm and a temperature of 279 K is found to occupy a volume of 568 milli
DIA [1.3K]

Answer: 0.025 moles of nitrogen gas are there in the sample.

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1.03 atm

V = Volume of gas = 568 ml = 0.568 L   (1L=1000ml)

n = number of moles  = ?

R = gas constant =0.0821Latm/Kmol

T =temperature =279K

n=\frac{PV}{RT}

n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles

0.025 moles of nitrogen gas are there in the sample.

4 0
3 years ago
The stability of atomic nuclei seem to be related to the ratio of _____.
Andru [333]
<span>Neutrons to protons. Neutrons and protons are tiny particles that are within the nucleus. Neutrons and protons make up the nucleus of the cell and the ratio of neutrons determine the stability of the atomic nuclei. The nucleus will become unstable if the ratio of neutrons to protons are not within the appropriate amount.</span>
6 0
3 years ago
Read 2 more answers
How can i prove that nascent oxygen more reactive than normal oxygen ?
laila [671]
Nascent oxygen has much higher reactivity than the oxygen bubbled through the reaction mixture. It doesn't stay nascent for long (you are right about it being converted quick to just O2), which is why it has to be generated in situ
6 0
3 years ago
In a certain experiment, 28.0 mL of 0.250 M HNO3and 53.0 mL of 0.320 M KOH are mixed. Calculate the number of moles of water for
Xelga [282]

Answer:

The number of moles of water formed in the resulting reaction is 6.03

[H+]: 37,2 M

[OH-]: 37,2 M

Explanation:

HNO3  +  KOH ----> KNO3 + H2O

First, we must discover the limiting reagent and we need to find out the moles, we use for this.

Moles that are used = Molarity / volume

HNO3 : 0,250 mol/L / 0,028L = 8,93 moles

KOH : 0,320 mol/L / 0,053L = 6,03 moles

The ratio of the reagents by stoichiometry is 1 to 1, so the limiting reagent is KOH, if I need 1 mole of nitric per mole of KOH, for every 8.93 moles I will need the same. However I have only 6.03 moles of KOH

The ratio of the reagents/products by stoichiometry is 1 to 1 so if I need 1 mol of KOH to make 1 mol of Water, 6,03 moles of KOH are used to make 6,03 moles of H2O.

The equilibrium of water is this:

2H2O ⇄ H3O+  +  OH-

2 moles of water are broken down into 1 mole of hydronium (H3O +) and 1 mole of hydroxyl (OH-)

6,03 moles of water are broken down into the half of those moles, so we have 3,015 moles of H3O+ and 3,015 moles of OH- but these moles are in 81,0 mL (the volume of the two solutions, 28 mL + 53 mL)

We must find out the moles in 1000 mL (1 L) so let's apply the rule of three.

81 mL ____ 3,015 moles

1000 mL ___ ( 1000 . 3,015) /81 = 37,2 M

7 0
2 years ago
21 mL It required 42.35 mL of H2SO4 to neutralize 21.17 mL of 0.5000 M NaOH. Calculate the concentration of H2SO4
bija089 [108]
The balanced equation for the above reaction is 
2NaOH + H₂SO₄ ---> Na₂SO₄ + 2H₂O
stoichiometry of NaOH to H₂SO₄ is 2:1
number of NaOH moles required-0.5000 M / 1000 mL/L x 21.17 mL = 0.010585 mol
According to stoichiometry, acid moles required are 1/2 of the base moles reacted
Therefore number of H₂SO₄ moles reacted - 0.010585 /2  mol
Number of moles in 42.35 mL of H₂SO₄ - 0.010585 /2 mol
Therefore in 1 L solution - (0.010585) /2 / 42.35 mL x 1000 mL/L = 0.125 M
Molarity of H₂SO₄ - 0.125 M
5 0
3 years ago
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