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rjkz [21]
3 years ago
10

Calculate the energy needed to raise the temperature of 42 grams of water from 25.0 degrees Celsius to 48 degrees Celsius. The s

pecific heat of water is 4.18 J/g.C
A. 8266 joules
B. 8266 calories
C. 4038 joules
D. 4038 calories
Chemistry
2 answers:
erica [24]3 years ago
7 0

Answer:

b

Explanation:

7nadin3 [17]3 years ago
4 0

Answer:

option B is the answer.

B. 8266 calories

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How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with
konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = a=31 cm^2

Thickness of the gold plating  = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3

Density of the gold = d=19.3 g/cm^3

m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g

Moles of gold = \frac{29.915 g}{197 g/mol}=0.152 mol

Au^{3+}+3e^-\rightarrow Au

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

\frac{3}{1}\times 0.152 mol=0.456 mol of electrons

Number of electrons = N =0.456\times \times 6.022\times 10^{23}

Charge on single electron = q=1.6\times 10^{-19} C

Total charge required = Q

Q=N\times q

Amount of current passes = I = 8 Ampere

Duration of time  = T

I=\frac{Q}{T}

T=\frac{N\times q}{I}

=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0
3 years ago
Scientists use what properties to help them identify and classify matter
Volgvan
Scientists use the physical and chemical properties to help them identify and classify matter. These physical and chemical properties are in a macro-perspective, in which these matter contains compounds, elements and atoms. Hence, matter can be classified in various ways, <span><span>
1.    </span>Atomic number either atomic mass each element has</span> 
<span><span>2.    </span>By substance of that matter either pure substance or mixed substance</span> <span>
3.    If they cannot reduce a certain substance into a much smaller quantified atomic structure then they they’ll use (2) to identify and classify it.</span>
5 0
3 years ago
The best reading for the volume of the gas in the syringe in the picture shown right is
spayn [35]

Answer:

48.5 mL , just did it on edge

6 0
3 years ago
Which of the following electron configurations describes an element that is a noble gas?
butalik [34]

Answer:

The answer to your question is: letter D.

Explanation:

Noble gases are located in group VIIIA of the periodic table, this means that they have 8 eight electrons in their outermost shell.

Due to this characteristic, they are stable and do not react with other elements.

a. 1s22s22p4    The outermost shell of this electron configuration has 6 electrons, then this element has 6 electrons not 8. This configuration is of an element of the group VIA.

b. [Ne]2s22p2  The outermost shell of this element has 4 electrons, so this is not the configuration of a noble gas.

c. [Ar] 3s1  This element only has one electron in its outermost shell, so this is the electron configuration of an alkaline metal.

d. 1s22s22p6 This element has 8 electrons in its outermost shell, so this is the electron configuration of a noble gas.

5 0
3 years ago
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Could anyone help me with question 3?
Gwar [14]
Second one i think.......
3 0
3 years ago
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