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rjkz [21]
2 years ago
10

Calculate the energy needed to raise the temperature of 42 grams of water from 25.0 degrees Celsius to 48 degrees Celsius. The s

pecific heat of water is 4.18 J/g.C
A. 8266 joules
B. 8266 calories
C. 4038 joules
D. 4038 calories
Chemistry
2 answers:
erica [24]2 years ago
7 0

Answer:

b

Explanation:

7nadin3 [17]2 years ago
4 0

Answer:

option B is the answer.

B. 8266 calories

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Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.
nordsb [41]

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

5 0
3 years ago
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A redox reaction can also be a?
AveGali [126]
Losing eltron is the answer
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true or false The atoms in Container A are hydrogen atoms. Hydrogen is a gas. The atoms placed in containers E, F, G, and H will
sleet_krkn [62]

Answer:

False

Explanation:

7 0
2 years ago
What is amount of energy released by the reaction?
Anettt [7]

Answer:

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3 years ago
What is the percentage composition of each element in Fe(OH)3
Bezzdna [24]

Answer:

Fe =52.2%, O = 44.9%, H = 2.81%

Explanation:

Percentage composition is also known as percentage by mass.

First, find the Mr of the compound.

Mr of Fe(OH)₃ = 55.8 + (16 × 3) + (1 × 3)

= 106.8

Now Divide the mass of the element, as per the compound, by the Mr of the compound found and times that by 100.

% composition of Fe = \frac{55.8}{106.8} × 100 = 52.2%

% composition of O = \frac{16*3}{106.8} × 100 = 44.9%

[There are 3 oxygen atoms in the compound Fe(OH)₃, so we will multiply the atomic mass of oxygen with the number of atoms in the compound: 16×3 ]

% composition of H = \frac{1*3}{106.8} × 100 = 2.81%

[There are 3 hydrogen atoms in the compound Fe(OH)₃, so we will multiply the atomic mass of hydrogen with the number of atoms in the compound: 1×3 ]

3 0
2 years ago
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