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Travka [436]
3 years ago
10

vin went fishing and caught 3 fish. The first fish weighs 1.75 pounds. The second fish weighs 2.4 pounds, and the third fish wei

ghs 0.95 pounds. How many pounds of fish did Kevin catch?
Mathematics
2 answers:
IRINA_888 [86]3 years ago
4 0
Vin went fishing it doesn't say anything about Kevin going fishing but if Vin and Kevin are the same person then it would be 5.1
kkurt [141]3 years ago
4 0
5.1 pounds fish with a average of 1.7

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There are 13 pints in 6 quarts and 1 pint.

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What is the relationship among proportional relationships lines, rates of change, and slope?
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Work out the value of a and b in the identity.<br> 3ax + 6 - 4(x + b)= 11x + 14
Levart [38]

Answer:

a=5, b=-2

Step-by-step explanation:

If you simplify the equation, you get:

3ax +6 -4x -4b - 11x - 14 = 0 =>

3ax - 15x -4b -8 = 0

group together x's and constants:

(3a-15)x -8 -4b = 0

To make this 0 for all x, we have to find an a such that 3a-15 = 0 and b such that -8-4b = 0. this leads to a=5, b=-2

5 0
4 years ago
There are 10 boys and 8 girls in the chess club at West Middle School. The principal randomly selects one student from the chess
egoroff_w [7]

Answer:

5/9 of a chance

Step-by-step explanation:

or a 55.55- chance

5 0
4 years ago
Marty made a $220 bank deposit using $10 bills and $5 bills. She gave the teller a total of 38 bills, how many $5 bills were in
Luda [366]

ANSWER: 32 five-dollar bills

======

EXPLANATION:

Let x be number of $5 bills

Let y be number of $10 bills

Since we have total of 38 bills, we must have the sum of x and y be 38

x + y = 38 (I)

Since the total amount deposited is $220, we must have the sum of 5x and 10y be 220 (x and y are just the "number of" their respective bills, so we multiply them by their value to get the total value):

5x + 10y = 220 (II)

System of equations:

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ 5x + 10y &= 220 && \text{(II)} \end{aligned} \right.

Divide both sides of equation (II) by 5 so our numbers become smaller

\left\{ \begin{aligned} x + y &= 38 && \text{(I)} \\ x + 2y &= 44 && \text{(II)} \end{aligned} \right.

Rearrange (I) to solve for y so that we can substitute into (II)

\begin{aligned} x + y &= 38 && \text{(I)} \\ y &= 38 - x \end{aligned}

Substituting this into equation (II) for the y:

\begin{aligned} x + 2y &= 44 && \text{(II)} \\ x + 2(38 - x) &= 44\\ x + 76 - 2x &= 44 \\ -x &= -32 \\ x &= 32 \end{aligned}

We have 32 five-dollar bills

======

If we want to finish off the question, use y = 38 - x to figure out number of $10 bills

y = 38 - 32 = 6

32 five-dollar bills and 6 ten-dollar bills

7 0
3 years ago
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