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2 years ago

Finding the center of Gravity:

Physics

2 answers:

ValentinkaMS [17]2 years ago

6 0

The answer is:

xA = 0

XB = 0

XC = 10.0.

The explanation:

1) From the given figure we can see that the coin B lies at the origin with coordinates (0,0).

2) and the coins A, B and C on the corners of a square.

3) The length of all sides in a square are equal. The distance between B and C form a side of a square.

4) So distance from B to C is 10 cm. Likewise, distance from B to A is also 10 cm.

5) and when B is located at point (0,0) and C is 10 units right of B, so coordinates of C will be (10,0).

6) A is located 10 units above B, so coordinates of A will be (0, 10).

7) Therefore, the x-coordinates of A, B and C are 0,0 and 10 respectively.

Leokris [45]2 years ago

6 0

The X-coordinate of the coin A is $\boxed{0\,{\text{cm}}}$ , coin B is $\boxed{0\,{\text{cm}}}$ and coin C is $\boxed{10\,{\text{cm}}}$ .

Further Explanation:

The three coins A, B , C are placed in the XY plane and they are placed along the X and Y axes. The X-coordinate of the coin is the value on X-axis at which they are placed.

The coin A is placed at the $10\,{\text{cm}}$ mark on the Y- axis and if we carefully look at its position along the X axis, then it will cross the X axis at the point $x = 0\,{\text{cm}}$ . Therefore, the X-coordinate for the coin A is $\boxed{{X_A} = 0\,{\text{cm}}}$ .

Now, the coin B is placed as the intersection of the X and the Y axis. The point of intersection of the two axis in a 2-D plane is termed as the origin. It means that from this point, the plane starts. At origin the X as well as Y coordinates are zero.

Therefore, the X-coordinate for the coin is $\boxed{{X_B}=0\,{\text{cm}}}$ .

The coin is placed at a distance of 10 cm from the coin B and it is placed along the X-axis. The X-coordinate of any point along the X-axis is the distance of the point from the origin. Therefore, the X-coordinate of the coin C is $\boxed{{X_C}=10\,{\text{cm}}}$ .

Thus, the X-coordinate of the coin A is $\boxed{0\,{\text{cm}}}$ , coin B is $\boxed{0\,{\text{cm}}}$ and coin C is $\boxed{10\,{\text{cm}}}$ .

Learn More:

1. What type of mirror do dentist use brainly.com/question/997618

2. What is ax, the x-component of the object's acceleration brainly.com/question/7114558

3. The amount of kinetic energy an object has depends on its brainly.com/question/137098

Answer Details:

Grade: High School

Subject: Physics

Chapter: Units and Measurements

Keywords: Three identical coins, A, Band C, three corners of a square, 10cm on a side, X-coordinates, origin, distance from the origin, X-axis, Y-axis.

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Which components of static electricity does a photocopier use?

Salsk061 [2.6K]

Answer:

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1 year ago

An aluminum cylinder with a radius of 2.7 cm and a height of 67 cm is used as one leg of a workbench. The workbench pushes down

soldier1979 [14.2K]

Answer:

$1.9\times 10^{-4}$

$1.2\times 10^{-4}\ m$

Explanation:

r = Radius = 2.7 cm

F = Force = $3.2\times 10^4\ N$

A = Area = $\pi r^2$

$\sigma$ = Stress = $\frac{F}{A}$

E = Young's modulus = $7\times 10^{10}\ Pa$

$\epsilon$ = Strain

$L_0$ = Original length = 67 cm

$\Delta L$ = Change in length

Young's modulus is given by

$E=\frac{\sigma}{\epsilon}\\\Rightarrow \epsilon=\frac{\sigma}{E}\\\Rightarrow \epsilon=\frac{\frac{3.2\times 10^4}{\pi 0.027^2}}{7\times 10^{10}}\\\Rightarrow \epsilon=0.0001996=1.9\times 10^{-4}$

Strain is $1.9\times 10^{-4}$

Strain is given by

$\epsilon=\frac{\Delta L}{L_0}\\\Rightarrow \Delta L=\epsilon\times L_0\\\Rightarrow \Delta L=1.9\times 10^{-4}\times 0.67\\\Rightarrow \Delta L=0.0001273\\\Rightarrow \Delta L=1.2\times 10^{-4}\ m$

The cylinder height decreases by $1.2\times 10^{-4}\ m$

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2 years ago

What is the name of the protein did the human use to create dogs?

Margaret [11]

Humans did not create dogs.

Humans have never created any new living species.

So far, the only one who can do that is You Know Who.

3 0

3 years ago

An object has a kinetic energy of 275 j and the momentum of magnitude of 25.0 kg m/s. find the speed and mass of the object

lyudmila [28]

<span>Recall formula for Kinetic energy is: KE = 1/2mv^2, where KE = 275J and momentum (which is 25.0 kg m/s) = m*v Therefore substitute for KE and mv in the equation above to get speed => 275 = 0.5 * 25 * v v = 275/12.5 v = 22m/s to get mass m, recall momentum = m*v => 25= 22*m m= 25/22 = 1.3663kg</span>

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3 years ago

A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/

Artyom0805 [142]

Answer:

$I=182.97\ kg-m^2$

Explanation:

Given that,

Radius of a spherical shell, r = 0.7 m

Torque acting on the shell, $\tau=860\ N$

Angular acceleration of the shell, $\alpha =4.7\ m/s^2$

We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :

$\tau=I\alpha$

I is the rotational inertia of the shell

$I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2$

So, the rotational inertia of the shell is $182.97\ kg-m^2$ .

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3 years ago