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DaniilM [7]
3 years ago
9

3. Suppose that an airplane flying 60 m/s, at a height of 300m, dropped a sack of flour (pere the effect

Physics
1 answer:
Arlecino [84]3 years ago
3 0

469.24m. An airplane flying 60m/s at a height of 300m dropped a sack of flour that stack the ground 469.24m from the point of release.

This is a example of horizontal parabolic projectile motion,and we represents this motion in the coordinate axis, which means that the velocity has components in x axis and y axis.

The equation of components on the x axis.

v_{0}x=\frac{x}{t}, where x is the distance and Vox the initial velocity before the drop

The equation of components on the y axis.

y = v_{0}yt+\frac{gt^{2} }{2}, where y is the height, and the velocity in y component before the drop is 0, reducing the equation to y = \frac{gt^{2} }{2}

Clear t from both the equation of components on the x axis and the y axis:

t=\frac{x}{v_{0} x} and t=\sqrt{\frac{2h}{g}}

Equating both equations and clearing the distance x:

\frac{x}{v_{0} x}=\sqrt{\frac{2h}{g}}\\x={v_{0} x}\sqrt{\frac{2h}{g}}

Substituting the values:

x=60\frac{m}{s} \sqrt{\frac{2(300m)}{9.81\frac{m}{s^{2} } }}=469.24m

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Explanation:

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3 years ago
A 52-kg snow skier is at the top of a 245-m-high hill. After she has gone down a vertical distance of 112 m, what is her total e
Assoli18 [71]

Answer:

  a. 125 kJ

Explanation:

Her total energy is the same as the potential energy she had at the top of the hill:

  PE = mgh

  = (52 kg)(9.8 m/s^2)(245 m) = 124,852 J

  ≈ 125 kJ . . . . matches choice A

_____

After skiing down 112 m, some of her initial energy is converted to kinetic energy, and some remains as potential energy. We assume the ski slope is essentially frictionless, and air resistance is negligible.

7 0
3 years ago
a thundercloud whose base is 500m above the ground. The potential difference between the base of the cloud and the m ground is 2
kolezko [41]

Answer:

1.6×10⁻⁶ N.

Explanation:

From the question,

F = (V/r)q......................... Equation 1

Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.

Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.

Substitute these values into equation 1

F = [(200×10⁶ )/500]×4.0×10⁻¹²

F = 1.6×10⁻⁶ N.

3 0
3 years ago
What is the average velocity of the person taking this walk?
Butoxors [25]
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6 0
3 years ago
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What is the acceleration caused by gravity of the planet Earth?
Luda [366]
The general accepted value of acceleration due to gravity, g, is 9.81 m/s^2.

That is an approximation because being the acceleration of gravity due to the attraction of the earth its magnitude will depend on the distance from the point to the center of the planet Earth.

The value of g is determined by using the Newton's Universal Law of gravity:

F = G * m of Earth * m of body / (distance^2)

Wehre {G* m of Earth / (distance^2) } = g

G is a universal constant = 6.67 * 10 ^ -11 N*m^2 / kg^2

m of Earth = 5.98 * 10 ^ 24 kg 

distance = radius of Earth + height of the body

Given the the Earth is not a perfect sphere the radius varies. Also the height of the body varies.

If you take a mean radius of Earth of 6.37*10^6 m

you get

g = 6.67*10^-11 N*m^2/kg^2 * 5.98*10^24kg / (6.37*10^6 m)^2 = 9.83 m/s^2

Again, if you want a more precise value of g, you need to find the exact place where you are and then use the right r.



 
7 0
3 years ago
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