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lana66690 [7]
3 years ago
13

Sultan throws a ball horizontally from his window, 12 m above the garden. It reaches the ground after

Physics
1 answer:
Kay [80]3 years ago
8 0

Answer:

<h2>2.4</h2>

Explanation:

<h2><em>Hope it help mark as Brainlist</em></h2>
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A mango fruit drops from the top of it's tree which is 40 m. How long does it takes to reach the ground
IrinaVladis [17]
T=distance over speed
T=40m over 9.8ms
T=answer
4 0
3 years ago
Arrange the distances between Earth and various celestial objects in order from least to greatest. Use the conversion table to h
Kaylis [27]

distance to the star Betelgeuse: 640 ly

As we know that

1 ly = 63000 AU

also we know that

1AU = 1.5 \times 10^8 km

1 ly = 63000 (1.5 \times 10^8) = 9.45 \times 10^{12} km

So the distance of Betelgeuse = 640 ly

d_1 = 640 \times 9.45 \times 10^{12} = 6.05 \times 10^{15} m

distance to the star VY Canis Majoris: 3.09 × 10^8 AU

d_2 = 3.09\times 10^8 \times 1.5 \times 10^8 km

d_2 = 4.64 \times 10^{16} km

distance to the galaxy Large Magellanic Cloud: 49976 pc

1 pc = 3.262 ly = 3.262 \times 9.45 \times 10^{12} km

1pc = 3.08 \times 10^{13} km

now we have

d_3 = 49976 \times 3.08 \times 10^{13}

d_3 = 1.54 \times 10^{18} km

distance to Neptune at the farthest: 4.7 billion km

d_4 = 4.7 \times 10^9 km

now the order of distance from least to greatest is as following

1. distance to Neptune at the farthest

2. distance of Betelgeuse

3. distance to the star VY Canis Majoris

4. distance to the galaxy Large Magellanic Cloud

6 0
3 years ago
The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). W
FromTheMoon [43]

Answer:\alpha =30-4=26 rad/s^2

Explanation:

Given

Position of a car is  given by

\theta =t^3-2t^2-4t+10

and angular speed is \frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

angular acceleration is

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha

\alpha =6t-4

at t=5 s

\alpha =30-4=26 rad/s^2

4 0
3 years ago
A basketball referee tosses the ball straight up for the starting tipoff. at what velocity must a basketball player leave the gr
sladkih [1.3K]
Mgh=mv²/2

v=√2gh=√2·9.8·1.25=4.95m/s
5 0
3 years ago
A teacher wants to perform a classroom demonstration that illustrates both chemical and physical changes. Which would be the bes
anygoal [31]

Answer

D) burning a candle

Explanation

When burning a candle no new substance is form.

We have both physical and chemical change occuring.

Physical part: Melting of the solid wax and evaporation of the liquid forms the physical change.

Chemical part: burning of the wax vapour forms the chemical change.

7 0
2 years ago
Read 2 more answers
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