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IgorC [24]
3 years ago
8

A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular

circuit?
A. 4.8 V
B. 4.8 A
C. 387 V
D. 387 A
Physics
2 answers:
pochemuha3 years ago
5 0

The correct answer would be

C. 387 V

NeTakaya3 years ago
4 0
Answer:
387 volts

Explanation:
Ohm's law is used to relate voltage, current and resistance.
The formula is as follows:V = I * R
where:
V is the applied voltage (measured in volts)
I is the current flowing (measured in amperes)
R is the resistance (measured in ohm)

In the given, we have:
current (I) = 9 amperes
resistance (R) = 43 ohm

Substitute with the givens in the above formula to get the voltage as follows:
V = 9 * 43
V = 387 volts

Hope this helps :)
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Answer:

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1515v_a-(1125*67.4666668 ft/s)= 2640*30.67

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