Answer:
J = 0.7 N-s away from wall
Explanation:
Given that,
Mass of the ball, m = 0.2 kg
Initial speed of the ball, u = 2 m/s
Final speed of the ball, v = -1.5 m/s (as it rebounds)
Impulse is equal to the change in momentum. So,

So, the impulse given to the ball is 0.7 N-m and it is away from the wall. Hence, the correct option is (c).
Force on a proton when they are moving inside the magnetic field is given by

so here while protons are going upwards we can say its direction of velocity is towards +Y and magnetic field is towards us which is along +Z direction so they will have force due to this motion.
As per above equation of force we can have direction of force which is along +X direction.
So here both proton will bend towards +X direction and start moving in curved path.
Answer:
a) 25.5 µH
b) 22.95 mV
Explanation:
Induced emf in a inductor is given by
E = L * di/dt, where
E is the voltage of the circuit
L is the inductance of the circuit
di/dt if the rate of inductance
A
So we have
0.0037 = L * 145
L = 0.0037 / 145
L = 0.0000255
L = 25.5 µH
B
i(t) = 225t²
Recall that
E = L * di/dt, so that
E = 25.5 µH * |225t²|
Differentiating with respect to t, we have
E = 25.5 * 2 * 225t
E = 25.5 * 450t
Solving for t = 2,we get
E = 25.5 * 450(2)
E = 25.5 * 900
E = 22950 µV or
E = 22.95 mV
I am sorry I would answer this questions but I don’t have the options of the heart rates so I can give you the best answer
Answer:
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Explanation:


?

Now, let's find the mass:

plug the values
⇒
Multiply the numbers
⇒
Swap the sides of the equation
⇒
Divide both sides of the equation by 270.48
⇒
Calculate
⇒
kg
Hope I helped!
Best regards!!