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Alisiya [41]
3 years ago
5

How many grams of no2 are theoretically produced if we start with 1.20 moles of s and 9.90 moles of hno3?

Chemistry
1 answer:
Ierofanga [76]3 years ago
5 0

Answer:- Theoretically 7.20 moles of NO_2 are formed.

Solution:- The balanced equation for the reaction of Sulfur with nitric acid is---

S + 6HNO_3\rightarrow H_2SO_4 + 6NO_2 + 2H_2O

From balanced equation, 1 mol of sulfur reacts with 6 moles of nitric acid. So, 1.20 moles of sulfur would react with 6 x 1.20 = 7.20 moles of nitric acid.

9.90 moles of nitric acid are available. It means nitric acid is present in excess and sulfur is limited. So, the theoretical yield is calculated by 1.20 moles of sulfur as...

1.20 mol x (6 mol nitrogen dioxide/1mol S) = 7.20 mol NO_2

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Here we have to choose the right option which tells the moles of CaCl₂ will react with 6.2 moles of AgNO₃ in the reaction

2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

6.2 moles of silver nitrate (AgNO₃) will react with B. 3.1 moles of calcium chloride (CaCl₂).

From the reaction: 2AgNO₃ + CaCl₂→ 2AgCl + Ca(NO₃)₂

Thus 2 moles of AgNO₃ reacts with 1 mole of CaCl₂

Henceforth, 6.2 moles of AgNO₃ reacts with \frac{6.2}{2} = 3.1 moles of CaCl₂.

1 mole of CaCl₂ reacts with 2 moles of AgNO₃. Thus-

A. 2.2 moles of CaCl₂ will react with 2.2×2 = 4.4 moles of AgNO₃.

C. 6.2 moles of CaCl₂ will reacts with 6.2×2 = 12.4 moles of AgNO₃.

D. 12.4 moles of CaCl₂ will reacts with 12.4 × 2 = 24.8 moles of AgNO₃

Thus the right answer is 6.2 moles of AgNO₃ will react with 3.1 moles of CaCl₂.

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