How many grams of no2 are theoretically produced if we start with 1.20 moles of s and 9.90 moles of hno3?
1 answer:
Answer:- Theoretically 7.20 moles of are formed.
Solution:- The balanced equation for the reaction of Sulfur with nitric acid is---
From balanced equation, 1 mol of sulfur reacts with 6 moles of nitric acid. So, 1.20 moles of sulfur would react with 6 x 1.20 = 7.20 moles of nitric acid.
9.90 moles of nitric acid are available. It means nitric acid is present in excess and sulfur is limited. So, the theoretical yield is calculated by 1.20 moles of sulfur as...
1.20 mol x (6 mol nitrogen dioxide/1mol S) = 7.20 mol
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Answer: There are now 2.07 moles of gas in the flask.
Explanation:
P= Pressure of the gas = 697 mmHg = 0.92 atm (760 mmHg= 1 atm)
V= Volume of gas = volume of container = ?
n = number of moles = 1.9
T = Temperature of the gas = 21°C=(21+273)K= 294 K (0°C = 273 K)
R= Value of gas constant = 0.0821 Latm\K mol
When more gas is added to the flask. The new pressure is 775 mm Hg and the temperature is now 26 °C, but the volume remains same.Thus again using ideal gas equation to find number of moles.
P= Pressure of the gas = 775 mmHg = 1.02 atm (760 mmHg= 1 atm)
V= Volume of gas = volume of container = 49.8 L
n = number of moles = ?
T = Temperature of the gas = 26°C=(26+273)K= 299 K (0°C = 273 K)
R= Value of gas constant = 0.0821 Latm\K mol
Thus the now the container contains 2.07 moles.